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pogonyaev
3 years ago
6

Which of the following indicates the subtraction property of equality when solving the equation 4(x + 9) + 5 = 3x − 8? answers:

4(x + 9) = 3x − 8 − 5 4x + 36 + 5 = 3x − 8 4(x + 9) − 5 + 8 = 3x x = −49
Mathematics
1 answer:
11111nata11111 [884]3 years ago
6 0

Answer:

4x+36+5=3×-8 is the answer

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In the xy -coordinate plane, the coordinates of point s are (-2,-6), and coordinates of point T are (18,9). Point Q lies on line
ira [324]

Answer:

(6,0)

Step-by-step explanation:

The coordinates of the points dividing the line segment in ratio m:n can be calculated as:

(\frac{mx_{2}+nx_{1}}{m+n} ,\frac{my_{2}+ny_{1}}{m+n} )

Here x1, y1 are the coordinates of first point S (-2, -6) and x2, y2 are the coordinates of second point T(18, 9).

In this case m will be 2 and n will be 3 as the ratio is 2:3

Using all these values we can find the coordinates of point Q

( \frac{2(18)+3(-2)}{2+3},\frac{2(9)+3(-6)}{2+3} )\\\\ = (\frac{30}{5} ,\frac{0}{5} )\\\\ =(6,0)

Thus, the coordinates of point Q which divides the line segment ST in ratio of 2:3 are (6,0)

5 0
3 years ago
HELP PLEASE NEED THIS DONE
givi [52]

Answer:

Step-by-step explanation:

A

4 0
3 years ago
Read 2 more answers
the height of two is recorded after 1, 2, and 3 weeks as shown in the graph at the right. which plants' growth represents a prop
vagabundo [1.1K]
For the more amount of the time the larger it will grow.
6 0
3 years ago
A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y = 5 − x 2 . What are the dimensions
kherson [118]

Answer:

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

y=5−x^2. What are the dimensions of such a rectangle with the greatest possible area?

Width =

Height =

Width =√10 and Height = \frac{10}{4}

Step-by-step explanation:

Let the coordinates of the vertices of the rectangle which lie on the given parabola y = 5 - x² ........ (1)

are (h,k) and (-h,k).

Hence, the area of the rectangle will be (h + h) × k

Therefore, A = h²k ..... (2).

Now, from equation (1) we can write k = 5 - h² ....... (3)

So, from equation (2), we can write

A =h^{2} [5-h^{2} ]=5h^{2} -h^{4}

For, A to be greatest ,

\frac{dA}{dh} =0 = 10h-4h^{3}

⇒ h[10-4h^{2} ]=0

⇒ h^{2} =\frac{10}{4} {Since, h≠ 0}

⇒ h = ±\frac{\sqrt{10} }{2}

Therefore, from equation (3), k = 5 - h²

⇒ k=5-\frac{10}{4} =\frac{10}{4}

Hence,

Width = 2h =√10 and

Height = k =\frac{10}{4}.

8 0
3 years ago
The graph of the function f is shown. The domain of f is [0,50]. What is the range of g(x)=4f(x)?
sergij07 [2.7K]

Answer:

The range of g(x) is [0,7].

Step-by-step explanation:

We must remember that range of function f(x) corresponds to the set of values of y in the graph (+y direction). Given that g(x) is a stretched version of f(x), the range of g(x) corresponds to the range of f(x) multiplied by 4. Then,

Ran\{g(x)\} = 4\cdot Ran\{f(x)\}

Ran\{g(x)\} = 4\cdot [0,1.75]

Ran\{g(x)\} = [0, 7]

The range of g(x) is [0,7].

4 0
3 years ago
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