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3 years ago

Is (-1,1) a solution for the systemy=2x=3y=-x

Mathematics

1 answer:

nadya68 [22]3 years ago

7 0

Answer:

Yes

Step-by-step explanation:

Substitute the x and y values of the point into the x and y values of the equation.

$1=2(-1)+3\\1=-2+3\\1=1\\:)\\\\1=-(-1)\\1=1\\:)$

Hope this helped!

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How do you solve this?

tatyana61 [14]

Use PEMDAS
figure out everything inside the parentheses first, you still have to do PEMDAS inside of the parentheses also.
I will attach an image of how I got the first answer -7,867, sorry if my handwriting is sorta sloppy

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2 years ago

How do you solve for Y in x=5 +8y-8

Rzqust [24]

x = 5 + 8y - 8

Combine like terms.

x = -3 + 8y

Add 3 to both sides.

x + 3 = 8y

Divide both sides by 8.

y = $\frac{x+3}{8}$

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2 years ago

How much is a milliliter

Sphinxa [80]

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3 years ago

Read 2 more answers

Calculate each or quotient 2 2/5 x3 1/3=

My name is Ann [436]

8

You multiply the numbers

6 0

3 years ago

please help. will give brainliest! review the table of values for function p(x). what is lim (x -14) p(x), if it exists? (table

Lubov Fominskaja [6]

Answer:

DNE

Step-by-step explanation:

The the given table, we have;

As x approaches -14 from the left, at x = -14.001, p(x) = 1.96

$\lim \limits _{x \to -14^{-}} p(x) = 1.96$

As x approaches -14 from the right, at x = -13.999, p(x) = 1.97

$\lim \limits _{x \to -14^{+}} p(x) = 1.97$

The value of p(x) when x = -14 is $\lim \limits _{x \to -14} p(x)$ = Undefined, or is not definable, therefore, p(x) Does Not Exist (DNE) when x = -14, and we have;

$\lim \limits _{x \to -14} p(x)$ Does Not Exist, DNE.

3 0

2 years ago