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Varvara68 [4.7K]
3 years ago
13

I need help I’m struggling

Mathematics
1 answer:
andrew-mc [135]3 years ago
8 0
All you need for a point to be left unchanged is it being on the line of reflection. (Generally speaking)

The first one is wrong cause you can have a line of reflection anywhere. If the line is horizontal ( x axis) then the slope would be zero. Whereas a line on y axis would be an undefined slope. There are also diagonal lines of reflections which have slopes

I am pretty sure the second one would be correct because, as previously stated, all the line needs to stay in the same place is it being on the line of reflection.

Again, lines of reflection do not have a set slope, a diagonal line of reflection going like / on the chart through the axis could have a slope of one, but it is not needed for the point to remain in the same place

The point does not necessarily need to be on the origin, it can be anywhere on the line of reflection, and if the line of reflection does not pass through the origin, a point on the origin would be moved in a reflection.

I hope this makes sense and helps you out a bit... have a good day
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Simplify 8 . 3 . X<br> A.13x<br> B.24x<br> C.22x<br> D.48x
olchik [2.2K]

Answer:

D. 48x

Step-by-step explanation:

sana nakatulong

6 0
3 years ago
What is an equation of the line that passes through the point (-7,-6)(−7,−6) and is parallel to the line x-y=7x−y=7?
kotykmax [81]

Answer:

y = x + 1

Step-by-step explanation:

The gradient of a line can be defined by the equation:

m (gradient) = (y1 – y2 ) ÷ (x1 – x2) ----> "1" and "2" should be in subscript

For (-7,-6) we use x2 and y2 (because this point can be anywhere along a line):

x2 = -7, y2 = -6

Plug these values into the formula above:

m = (y-(-6)) ÷ (x-(-7))

m = (y+6) ÷ (x+7)

At this stage, the equation can't be solved as there are two unknowns. Therefore, the gradient must be found another way. Two lines are parallel if they have the same gradient - in their y=mx+c equations, m will be equal.

x - y=7 is the line alluded to in the question. Rearranging this equation into the line equation format gives:

y = x-7 ---> The gradient (coefficient of x) is 1.

Therefore, the gradient of the other parallel line must also be 1.

This can be substituted into the previous equation to give:

1 = (y+6)÷(x+7)

x+7 = y+6

x+1 = y

Therefore, the answer is y=x+1

5 0
3 years ago
Miguel reads 3/4 chapters in 4/5 hours. What is the unit rate in chapters per hour?
kap26 [50]
If its multiplication sipmlest form is, 6/10
If its addition simplest form is, 7/9
If its any other just tell me! Hope i was right :p
8 0
4 years ago
.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and
Leni [432]

Answer:

a) Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

b) t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

Step-by-step explanation:

Information given

\bar X=130 represent the sample mean for the amount spent each shopper

s=40 represent the sample standard deviation

n=80 sample size  

\mu_o =120 represent the value to verify

t would represent the statistic    

p_v represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:  

Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

5 0
4 years ago
Pls help asap!(this question is worth 20 points!)picture down below says question
diamong [38]

Answer:

138

Step-by-step explanation:

c=5

d=4

6c^2-5d+8

substitute c & d

6(5)^2-5(4)+8

6(25)-20+8

150-20+8 = 138

3 0
3 years ago
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