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Varvara68 [4.7K]
3 years ago
13

I need help I’m struggling

Mathematics
1 answer:
andrew-mc [135]3 years ago
8 0
All you need for a point to be left unchanged is it being on the line of reflection. (Generally speaking)

The first one is wrong cause you can have a line of reflection anywhere. If the line is horizontal ( x axis) then the slope would be zero. Whereas a line on y axis would be an undefined slope. There are also diagonal lines of reflections which have slopes

I am pretty sure the second one would be correct because, as previously stated, all the line needs to stay in the same place is it being on the line of reflection.

Again, lines of reflection do not have a set slope, a diagonal line of reflection going like / on the chart through the axis could have a slope of one, but it is not needed for the point to remain in the same place

The point does not necessarily need to be on the origin, it can be anywhere on the line of reflection, and if the line of reflection does not pass through the origin, a point on the origin would be moved in a reflection.

I hope this makes sense and helps you out a bit... have a good day
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Write the expression for when you translate the graph of y = |3x− 5| one unit to the right. Plzz help
AfilCa [17]

Answer:

2<x<4/3

Step-by-step explanation:

Given the equation of a graph to be y = |3x− 5|, if the equation is one unit to the right, this can be expressed as |3x-5| > 1.

Solving the resulting equation

|3x-5| > 1.

Since the function 3x-5 is in a modulus sign, this means that the function can take both negative and positive values.

For positive value of the function;

+(3x-5) > 1

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For the negative value of the function;

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On expansion

-3x+5 > 1

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Multiplying through by -1 will also change the inequality sign

x < -4/-3

x < 4/3...(2)

Combining equation 1 and 2, we have;

2<x<4/3

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3 years ago
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Answer:

41

Step-by-step explanation:

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