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tensa zangetsu [6.8K]
3 years ago
7

A box contains five slips of paper. Each slip has one of the number 4, 6, 7, 8, or 9 written on it and all numbers are used. The

first player reaches into the box and draws two slips and adds the two numbers. If the sum is even, the player wins. If the sum is odd, the player loses.
a. What is the probability that the player wins?

b. Does the probability change if the two numbers are multiplied? Explain.
Mathematics
1 answer:
max2010maxim [7]3 years ago
6 0
A. If the player chooses 6, 4, and 8 each time, they have 3/5 chances to win.

6+4= 10

6+8= 14

8+4= 12

These are all even so as long as they get one of these combinations they will win

b. All three combinations still work when multiplied

6*4=24
6*8=48
8*4= 32
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What is <br>2 divided by 192? ​
astra-53 [7]

Answer:

192/2 = 96 because is just the half of the number

5 0
3 years ago
Metal A has a density of 12.7 g/cm3.
stira [4]

Using the given information, the density of metal B is 8.58 g/cm³

<h3>Calculating density </h3>

From the question, we are to determine the density of metal B

From the given information,

55 g of metal A is combined with metal B to create an alloy with mass 90 g

∴ Mass of metal B in the alloy = 90 g - 55 g = 35 g

Now, we will determine the volume of metal A in the alloy

Using the formula,

Density = Mass / Volume

∴ Volume = Mass / Density

Volume of metal A in the alloy = 55/12.7

Volume of metal A in the alloy = 4.33 cm³

Then, we will determine the volume of the alloy

Volume of the alloy = 90/10.7

Volume of the alloy = 8.41 cm³

∴ Volume of metal B in the alloy = 8.41 cm³- 4.33 cm³

Volume of metal B in the alloy = 4.08 cm³

Now, for the density of metal B

Density = mass / volume

Density of metal B = 35 / 4.08

Density of metal B = 8.58 g/cm³

Hence, the density of metal B is 8.58 g/cm³.

Learn more on Calculating density here: brainly.com/question/13986137

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5 0
2 years ago
A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the
Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of​ metal

y ----> the original width of the piece of​ metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in

The volume of the box is equal to

V=(x-10)(y-10)5

V=930\ in^3

so

930=(x-10)(y-10)5

simplify

186=(x-10)(y-10) -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

so

x=y+25 ----> equation B

substitute equation B in equation A

186=(y+25-10)(y-10)

solve for y

186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

x=16+25=41

therefore

The original length was 41 inches and the original width was 16 inches

3 0
3 years ago
I NEED HELP WITH THIS PLEASE!!!!!
kumpel [21]

Answer:

nt ooooo

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Step-by-step explanation:

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2 years ago
A bag contains 10 red marbles, 15 green marbles, and 15 blue marbles. If Dawshawn draws a marble from the bag, what is the proba
Lyrx [107]

Answer:

10/40 or a 1 in 4 chance he will grab a red marble

Step-by-step explanation:

You add up all of the marbles;

10+15+15

40

Now you take the number of red marbles are divide it by 40;

10/40

That is your answer.

5 0
3 years ago
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