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azamat
3 years ago
13

4x +6y =0

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
4 0
Here, x - 2y = 14
x = 14 + 2y

Now, substitute this value into first equation, 
4x + 6y = 0
4(14 + 2y) + 6y = 0
56 + 8y + 6y = 0
14y = -56
y = -56/14
y = -4

Substitute it into second equation, 
x = 14 + 2(-4)
x = 14 - 8
x = 6

In short, Your Answer would be: (6, -4)

Hope this helps!
stiks02 [169]3 years ago
3 0
Subsitute
first solve for a single variable
solve for x in the 2nd ones

x-2y=14
add 2y
x=2y+14
sub that for x


4(2y+14)+6y=0
8y+56+6y=0
14y+56=0
minus 56 both sides
14y=-56
divide both sides by 14
y=-4
sub back

x=2y+14
x=2(-4)+14
x=-8+14
x=6

(x,y)
(6,-4)
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Assuming the exponent is supposed to be "^2" your equation will read:

4x² + 8x - 5

It must set equal to y to be a valid function and the y must be set equal to zero to find x-intercepts.

4x² + 8x - 5 = 0
4x² - 2x + 10x - 5 = 0
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(2x + 5)(2x - 1) = 0

Set each binomial equal to zero.

2x + 5 = 0
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2x = - 5
Divide both sides by 2
x = - 5/2

2x - 1 = 0
2x = 0 + 1
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x = 1/2

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2 years ago
What is the y-intercept of the graph of the function f(x) = x^2 + 3x + 5?
Semenov [28]

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(0,5)

Step-by-step explanation:

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y=0+0+5

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If\ f(x)=2\sqrt{x}-2,\ then\\\\The\ domain:\boxed{x\in[0;\ \infty)}\\\\The\ range:\boxed{y\in[-2;\ \infty)}
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Work Shown:

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A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at
valina [46]

Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

Red = 5

White = 6

Black = 9

Required

The probability of selecting 2 same colors when the first is not replaced

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Total = 5 + 6 + 9

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This is calculated as:

P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)

So, we have:

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<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19}  + \frac{9}{20} * \frac{8}{19}

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P(Same)=\frac{61}{190}

4 0
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