Answer:
Base area of box = 
Step-by-step explanation:


Base area of a rectangular box is a rectangle
Area of a rectangle (base area)= length times width


Base area = 
Multiply x inside the parenthesis
Base area of box = 
Answer:
Part 2:
The shape of a banana cut in 45° angle is that of a curve that is closed with the appearance of a flattened circle or an oval similar to an ellipse therefore having two focal points
The drawing of the angle cross section of a cylinder representing the banana is attached
Part 3:
When the banana is cut in half, perpendicular to the base of the banana, the shape formed is circular withe the center of the banana being about the same location as the center of the circle
The drawing of the perpendicular cross section of a cylinder representing the banana is
Step-by-step explanation:
R * p = -37.8
Solve for either R or p.
R = -37.8/p
Now plug into R + p = 13.5
-37.8/p + p = 13.5
Solve for p.
After finding p, plug your p-value into either R + p or R*p to find R.
Take it from here.
Answer:
is the number of quarters and
is the number of dimes
Step-by-step explanation:
we know that


Let
x-----> the number of dimes
y------> the number of quarters
we know that
-----> equation A
----Isolate the variable y
-----> equation B
Substitute equation B in equation A
Find the value of y


therefore
is the number of quarters and
is the number of dimes
Answer:a) P(8 of the players numbers are drawn)=1.3×10^-8
b) P(7 of the players number are drrawn)=3.33×10^-c) P(at least 6 of the players number were drawn)=1.84×10^-4
Step-by-step explanation:
Players has 8 combinations of numbers from 1-40. The outcome S contains all the combinations of 8 out of 40
a) P(8 of the players numbers are drawn)= 1/40/8= 1.3×10^-8
There are one in hundred million chances that the draw numbers are precisely the chosen ones.
b) Number of ways of drawing 78 selected numbers from 1-40=8×(40-7)
8×32
P(7 of the players number are drawn)=8×32/40 =3.33×10^-6.
There are approximately 300,000 chances that 7 of the players numbers are chosen
c) P(at least 6 players numbers are drawn)= 32/2×(8/6) ways to draw.
P(at least 6 players numbers are drawn)=P(all 8 chosen are drawn)+P(7 players numbers drawn)+P(6 chosen are drawn) = 1+ 8 x32/40/8 +[8\6 ×32/2]
P(at least 6 players numbers are drawn) = 1.84×10^-4.
There are approximately 5400chances that at least6 of the numbers drawn are chosen by the player.