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3 years ago

What’s the answer but you also have to simplify

Mathematics

1 answer:

Jlenok [28]3 years ago

6 0

Answer:

The answer is 9x² + 3x - 2.

Step-by-step explanation:

1) Collect like terms.

$(7x^{2} + {2x}^{2} ) + ( - 2x + 5x) + (8 - 10)$

2) Simplify.

${9x}^{2} + 3x - 2$

Therefor, the answer is 9x² + 3x - 2.

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What are the terms or 8x+6

Bumek [7]

Answer:

14x. ....................

4 0

3 years ago

Cheryl solved a problem: 84 ÷ 0.01 = 8,400.

Alexandra [31]

Answer:

Cheryl is correct.

Step-by-step explanation:

Cheryl solved a problem : 84 ÷ 0.01 = 8,400.

This is absolutely right.

When we divide any whole number with the divisor having decimal, we change the divisor to a whole number before performing the division.

To do this, we multiply both the numbers (divisor and dividend) by the same power of 10, until the divisor is a whole number.

$\frac{84\times 10}{0.01\times 10}$ = $\frac{840}{0.1}$

to make divisor a whole number we will again multiply both the numbers by 10.

$\frac{840\times 10}{0.1\times 10}$ = $\frac{8400}{1}$ = 8,400

Now answer would be 8400.

Therefore, Cheryl is correct.

7 0

3 years ago

— 3х – 2y = 16 х+ 9y = 28

Alla [95]

Answer:

x=-8

y=4

Step-by-step explanation:

first you multiply this equation (-3x-2y=16) with negativ it will be like this 3x+2y=-16

3x+2y=-16

(x+9y=28)3 _multiply with 3

3x+2y=-16

3x+27y=84

use minus(-) =3x-3x=0

=2y-27y=-25y

=-16-84=-100

the result:-25y=-100

y=4

take any simple equation and replace y with 4

x+9y=28

x+9(4)=28

x+36=28

x=28-36

x=-8

answer:x=-8,y=4

5 0

3 years ago

Can someone please help, ty!! (Will mark brainliest)

Oliga [24]

Answer:

Arcadia

Step-by-step explanation:

the line in the box is the median and Arcadia is bigger than Millersburg

7 0

3 years ago

Read 2 more answers

A certain component is critical to the operation of an electrical system and must be replaced immediately upon failure. If the m

nekit [7.7K]

Answer:

Step-by-step explanation:

From the given information:

Assuming we have an integer c to represent the components in the stocks.

Thus, the needed probability can be expressed as:

$P(X_1+X_2+ ........ X_c \ge 2000)$

To break this down, we have:

$P(\sum X_i \ge 2000) = P \Bigg(\dfrac{\sum X_i - 100n}{\sqrt{n \ Var (X)}} \ge \dfrac{2000-100 n }{\sqrt{n \times 900}} \Bigg )$

$P \Bigg(\dfrac{\sum X_i - 100n}{\sqrt{n \ Var (X)}} \ge \dfrac{2000-100 n }{\sqrt{n \times 900}} \Bigg )= P (Z \ge 0.95 ) \ \ \ because \ Z_{0.05} = -1.65 \\ \\ \\ \dfrac{2000-100 n }{\sqrt{n \times 900}} = -1.65 \\ \\ \\ \dfrac{100\ n-2000 }{\sqrt{900n}} = 1.65 \\ \\ 100 n -1.65 \sqrt{900 n }-2000 = 0$

By solving the equation:

n = 23

Thus, relating to the needed condition; n ≥ 23

The needed number of the components that should be in stock should be at least 23.

5 0

3 years ago