Solve:
(3x-2)^2-4x(2x-3)>=0
(3x-2)(3x-2)-8x^2+12x>=0
9x^2-12x+4-8x^2+12x>=0
The solution: x^2+4>=0
I hope I helped you with your solution! If you could give me brainliest, I would be very thankful!
if ACE line is linear so you can say BCA angle plus BCE equal to 180 degree
Y - (-1/2) = 3(x - 2)
y + 1/2 = 3(x - 2)
Suppose an object starts moving at u and gains an acceleration of a. After time t, it gets a speed v after travelling a distance of s.
a = (v - u) / t => v - u = at
v = u + at
s = ut + 1/2(v - u) t
s = ut + 1/2 (at) t
s = ut + 1/2 at2
s = ut + 1/2 at2
v2 = (u + at)2
v2 =u2 + 2uat + a2t2
v2 = u2 + 2a (ut + 1/2 at2)
v2 = u2 + 2as
v2 = u2 + 2as
Answer:
The temperature at the start is 35F
The temperature of the room is 74F
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Step-by-step explanation:
Given

Solving (a): The temperature at the start.
To do this, we set: 
So, we have:




<em>Hence, the temperature at the start is 35F</em>
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Solving (b): The room temperature
We have:

To get the temperature of the room, we simply remove the exponential function.
So, we have:

<em>Hence, the temperature of the room is 74F</em>