notice... the dog's pen perimeter, does not include the side that's bordering the garden's, since that side will use the heavy duty fence, instead of the light one
so, the sum of both of those costs, will be the C(x)
so, just take the derivative of it, and set it to 0 to find the extremas, and do a first-derivative test for any minimum
Answer:
x = 0
, y = 4
Step-by-step explanation:
Solve the following system:
{y = 4 - 3 x | (equation 1)
x + 2 y = 8 | (equation 2)
Express the system in standard form:
{3 x + y = 4 | (equation 1)
x + 2 y = 8 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 x + y = 4 | (equation 1)
0 x+(5 y)/3 = 20/3 | (equation 2)
Multiply equation 2 by 3/5:
{3 x + y = 4 | (equation 1)
0 x+y = 4 | (equation 2)
Subtract equation 2 from equation 1:
{3 x+0 y = 0 | (equation 1)
0 x+y = 4 | (equation 2)
Divide equation 1 by 3:
{x+0 y = 0 | (equation 1)
0 x+y = 4 | (equation 2)
Collect results:
Answer: {x = 0
, y = 4
-4(2y)+11y=15, -8y+11y=3y=15: y=5
X=2(5)=10
To check your work -4(10)+11(5)=15
15=15
Answer:
m∠1=80°
m∠2=112°
m∠3=131°
m∠4=80°
m∠5=37°
Step-by-step explanation:
First you have to find m∠2
To do that find m∠6 (I created this angle shown in pic below)
Find m∠6 by using the sum of all ∠'s in a Δ theorem
m∠6=180°-(63°+49°)
m∠6=68°
Now you can find m∠2 with the supplementary ∠'s theorem
m∠2=180°-68°
m∠2=112°
Then you find m∠5 using the sum of all ∠'s in a Δ theorem
m∠5=180°-(112°+31°)
m∠5=37°
Now you can find m∠1
m∠1=180°-(63°+37°)
m∠1=180°-100°=80°
m∠4 can easily be found too now:
m∠4=180°-(63°+37°)
m∠4=80°
m∠3=180°-49°
m∠3=131°
Well 1/40 is 0.025 so that should be the write fraction to use
