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elixir [45]
3 years ago
5

If 7 buses can transport 280 persons how many persons can be carried by 12 buses

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
5 0

Answer:

480

Step-by-step explanation:

280/7 = 40

40x12 = 480

skelet666 [1.2K]3 years ago
3 0

Step-by-step explanation:

672 I'm pretty sure cus yea oop-

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What is the percentage of 377 of 325?
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Answer: 116%

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3 years ago
Please someone answer for this question
Maslowich
First one is 5/3
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A rectangle has a length of 34 inches less than 5 times it’s width. If the area of the rectangle is 867 square inches, find the
pshichka [43]

Length of the rectangle is 51 inches

<u>Solution:</u>

Given that

Length of the rectangle in 34 miles less than 5 times its width

Area of rectangle = 867 square inches

Need to determine length of the rectangle.

Let assume width of the rectangle be represented by variable x.

So 5 times width of the rectangle =5x

34 inches less than 5 times width of the rectangle = 5x – 34

As Length of the rectangle in 34 miles less than 5 times its width

=> Length of the rectangle = 5x – 34

<em><u>The formula for rectangle is given as:</u></em>

\text { area of rectangle }=length \times width

As given that Area of rectangle = 867 square inches

\begin{array}{l}{=>867=(5 x-34) \times(x)} \\\\ {=>5 x^{2}-34 x-867=0}\end{array}

On solving quadratic equation by using quadratic formula

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case a = 5, b = -34 and c = -867

On substituting value of a, b and c in quadratic formula we get

\begin{array}{l}{x=\frac{-(-34) \pm \sqrt{(-34)^{2}-4 \times 5 \times(-867)}}{2 \times 5}} \\\\ {=>x=\frac{34 \pm \sqrt{18496}}{10}=\frac{34+136}{10}} \\\\ {=>x=\frac{34+136}{10}=17 \text { or } x=\frac{34-136}{10}=-10.2}\end{array}

Since x represents width, it cannot be negative, so x = 17

Length of the rectangle = 5x – 34 = 5(17) – 34 = 51

Hence length of the rectangle is 51 inches

5 0
3 years ago
One fourth of a box of cereal was shared equally among 3 people. How much cereal did each person get?
just olya [345]
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6 0
3 years ago
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The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain riv
kari74 [83]
The river flows at 2 miles per hour. This is the speed of the current, or the speed at which the water itself is moving.

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For particles that are 15 times the usual mass, the speed of the river itself must increase for the particles to travel at the same speed as before. The mass of the particles is still proportional to the sixth power of the speed of the river, but the speed of the river can no longer be 2 miles per hour. It is some speed y, which we are solving for.

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To solve for y, we must take the sixth root of both sides, or raise both sides to the one-sixth power.

\sqrt[6]{y^6} =  \sqrt[6]{960}

Using a calculator, we see that \sqrt[6]{960} = 3.14 \ miles \ per \ hour.
6 0
4 years ago
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