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DaniilM [7]
3 years ago
8

A coin bank has 250 coins dimes and quarters worth 39.25 how many of each type of coins are there?

Mathematics
2 answers:
Maurinko [17]3 years ago
8 0
Set up a system of equations.

0.10d + 0.25q = 39.25
d + q = 250

Where 'd' represents the number of dimes, and 'q' represents the number of quarters.

d + q = 250

Subtract 'q' to both sides:

d = -q + 250

Plug in '-q + 250' for 'd' in the 1st equation:

0.10(-q + 250) + 0.25q = 39.25

Distribute 0.10:

-0.10q + 25 + 0.25q = 39.25

Combine like terms:

0.15q + 25 = 39.25

Subtract 25 to both sides:

0.15q = 14.25

Divide 0.15 to both sides:

q = 95

Now plug this into any of the two equations to find 'd':

d + q = 250

d + 95 = 250

Subtract 95 to both sides:

d = 155

So there are 95 quarters and 155 dimes.
bija089 [108]3 years ago
4 0
Coin bank= 250 coins
quarters worth=39.25
250-39.25=210.75 of coins there are
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Answer:

So:

Counting from a given time t = 0min, we know that:

Each 15 mins she removes the scones

Each 12 mins she removes the muffins

Each 10 mins she removes the cookies.

So when will she remove both at the same time?

Well, this will happen in the smallest common multiple of 15, 12 and 10.

or at LCM(10, 12, 15).

How we find it?

well, in this case is easy.

All the multiples of 10 end with a zero.

So let's find the multiples of 12 and 15 that also end with a zero:

12*6 = 60

15*4 = 60

and

10*6 = 60

So the LCM(10,12,15) = 60.

Another way is by calculating:

10*12*15/(GCF(10,12)*GCM(12,15)*GCM(10,15)

Where GCF = greatest common factor.

Between 10 and 12 is 2.

Between 12 and 15 is 3

Between 10 and 15 is 5.

Then:

10*12*15/(2*3*5) = 60.

This means that 60 minutes after she starts, she will remove the scones, muffins and cookies at the same time.

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A ball of radius 17 has a round hole of radius 7 drilled through its center. Find the volume of the resulting solid.
Ahat [919]

Answer:

<h3>19,133.067</h3>

Step-by-step explanation:

Volume of the ball (spherical in nature) Vb = 4/3πrb³

Volume of the hole Vh = 4/3πrh³

rb is the radius of the ball

rh is the radius of the hole

If a ball of radius 17 has a round hole of radius 7 drilled through its center, the volume of the resulting solid will be expressed as:

V = Vb - Vh

V = 4/3πrb³ - 4/3πrh³

factor out the like terms;

V = 4/3π(rb³-rh³)

Given

rb = 17

rh = 7

V = 4/3π(17³-7³)

V = 4/3π(4913-343)

V = 4/3π(4570)

V = (4π*4570)/3

V = 57,399.2/3

V = 19,133.067

Hence the volume of the resulting solid is 19,133.067

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