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2 years ago

Find the percent increase. Round to the nearest percent.

Mathematics

2 answers:

noname [10]2 years ago

8 0

Answer:

I think it's a 72.36% increase

Step-by-step explanation:

I'm not completely sure but that's what the calculator I used said..

yan [13]2 years ago

8 0

Answer:

Step-by-step explanation:

Find the amount of change.

Amount of change = Greater Value − Lesser Value

= 131 − 127 Substitute values.

= 4 Subtract.

Find the percent increase. Round to the nearest percent.

Percent Change =

Amount of Change

Original Amount

131

Substitute values.

≈ 0.03 Divide and round to the nearest hundredth.

= 3% Write as a percent.

The percent decrease is 3%.

pls press the heart if this was helpful

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jenyasd209 [6]

Answer:

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Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

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