Answer:
The area would be 1.35 meters, hope this helps!
Grade In Favor Opposed Undecided Total
9 4 2 8 14
10 7 11 8 26
11 14 15 9 38
12 11 5 10 26
Total 36 33 35 104
Above is a partial sum chart that will help us in our quest.
P(Grade 9 | opposed)
The probability of Grade 9, given opposed, is the portion of opposed students that are in grade 9.
Total number opposed: 33
Number opposed in Grade 9: 2
P(Grade 9 | opposed) = 2 / 33 = 0.06
P(opposed | Grade 9)
Total Number Grade 9: 14
Number opposed in Grade 9: 2
P(opposed | Grade 9) = 2 / 14 = 0.14
cos(37°15') = cos(37.25°) ≈ 0.7960
15' means 15/60 of a degree, or 0.25 degrees.
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Note: the calculator mode is set to <em>Degrees</em>.
Length of the box = 25 - 2x
Width of the box = 14 - 2x
Height of the box = x
a.) Volume of the box = x(25 - 2x)(14 - 2x) = x(350 - 50x - 28x + 4x^2) = 4x^3 - 78x^2 + 350x
Therefore, the function that models the volume of the box is V(x) = 4x^3 - 78x^2 + 350x
b.) 4x^3 - 78x^2 + 350x ≥ 240
4x^3 - 78x + 350x - 240 ≥ 0
x = 0.834, 5.438
The values of x for which the volume is greater than 240 in^3 is 0.834 ≤ x ≤ 5.438
c.) For maximum volume, dV/dx = 0
dV/dx = 12x^2 - 156x + 350 = 0
x = 2.882910931
Therefore, maximum volume = 4(2.882910931)^3 - 78(2.882910931)^2 +350(2.882910931) = 453.798 in^3
