Answer:
Ans; Base=19.799cm
each of the other two sides=14cm
Step-by-step explanation:
two isosceles triangles are going to give you a square. So that means the area of the square will be 2(98cm^2) cos u added two of the triangles.There fore to get each side of the square, find the square root of the area of the square.you will get 14cm.that is equal to the length of the other two sides of the triangle. the base of the triangle is equal to the diagonals of the square(d=s√2).Use that to find the base of the triangle. Hope this helps.I am not good at explaining though
(0, 5) is the minimum value.
Find the axis of symmetry by plugging the respective variables into -b/2a
-5/2(0) = 0
There is no b-value in our equation, or rather, the value of b is 0. To see this, y = 2x^2 + 5 can be written as
y = 2x^2 + 0x + 5
We plug 0 into f(x), establishing every x-value as 0.
f(0) = 2(0)^2 + 5
f(0) = 0 + 5
f(0) = 5
5 is now your vertex’s y-value. Plot the two values together.
(0, 5)
We know that this is a minimum because the leading coefficient is positive, meaning the the graph’s parabola will open down.
Answer:
5/12
Step-by-step explanation:
sorry if I'm incorrect can you mark brainiest please
Answer:
<em>0 < X < 40</em>
Explanation:
[ Leg A ] 13
[ Leg B ] 27
[ Leg C ] x
Since We Are Missing The Third Side Of The Triangle.
x Has To Be Greater Than 0 But Less Than 40
<span>I can be wrong, but I think that the answer is: To find the values of p, q, r and s, you should start by finding all factor pairs of the leading coefficiant and constant term. </span>
