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kherson [118]
3 years ago
8

Please help.............

Mathematics
1 answer:
o-na [289]3 years ago
7 0

Answer:

a. 754cm³ (3 s.f.)

b. 415cm² (3 s.f.)

Step-by-step explanation:

Formulas (for easier reference):

Volume of cone: \pir²\frac{h}{3}

Volume of hemisphere: \frac{2}{3}\pir³

Surface area of cone without base: \pirl

Surface area of hemisphere without base: 2\pir²

We can just apply the formulas for the question:

Volume of toy = (\pi × 6² × \frac{8}{3}) + (\frac{2}{3} × \pi 6³)

                        = 96\pi + 144\pi

                        = 240\pi

                        = 754cm³ (3 s.f.)

Surface area of toy = (\pi × 6 × 10) + (2 × \pi × 6²)

                                = 60\pi + 72\pi

                                = 132\pi

                                = 415cm² (3 s.f.)

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