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kherson [118]
3 years ago
8

Please help.............

Mathematics
1 answer:
o-na [289]3 years ago
7 0

Answer:

a. 754cm³ (3 s.f.)

b. 415cm² (3 s.f.)

Step-by-step explanation:

Formulas (for easier reference):

Volume of cone: \pir²\frac{h}{3}

Volume of hemisphere: \frac{2}{3}\pir³

Surface area of cone without base: \pirl

Surface area of hemisphere without base: 2\pir²

We can just apply the formulas for the question:

Volume of toy = (\pi × 6² × \frac{8}{3}) + (\frac{2}{3} × \pi 6³)

                        = 96\pi + 144\pi

                        = 240\pi

                        = 754cm³ (3 s.f.)

Surface area of toy = (\pi × 6 × 10) + (2 × \pi × 6²)

                                = 60\pi + 72\pi

                                = 132\pi

                                = 415cm² (3 s.f.)

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Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

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Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

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Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
3 years ago
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