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Hatshy [7]
3 years ago
14

Which of the following is an example of a rational function?

Mathematics
1 answer:
Andru [333]3 years ago
3 0

Answer:

the second one is an example of a rational function

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What is an equivalent exponential equation? log5(1/25)=−2
jenyasd209 [6]

\log_ab=c\iff a^c=b\\\\\log_5\dfrac{1}{25}=-2\iff5^{-2}=\dfrac{1}{25}\\\\5^{-2}=\dfrac{1}{5^2}=\dfrac{1}{25}

7 0
3 years ago
The hardcover version of a book weighs 7 ounces while its paperback version weighs 5 ounces. Forty-five copies of the book weigh
konstantin123 [22]

Answer:

33 copies were paperback and 12 were hardcover.

Step-by-step explanation:

Let h represent the number of hardcover copies and p represent the number of paperback copies.

We know that the total number of copies was 45; this gives us the equation

h+p = 45

We know that each hardcover copy is 7 ounces; this gives us the expression 7h.

We also know that each paperback copy is 5 ounces; this gives us the expression 5p.

We know that the total weight was 249 ounces; this gives us the equation

7h+5p = 249

Together we have the system

\left \{ {{h+p=45} \atop {7h+5p=249}} \right.

We will use elimination to solve this.  First we will make the coefficients of the variable p the same; to do this, we will multiply the top equation by 5:

\left \{ {{5(h+p=45)} \atop {7h+5p=249}} \right. \\\\\left \{ {{5h+5p=225} \atop {7h+5p=249}} \right.

To eliminate p, we will subtract the equations:

\left \{ {{5h+5p=225} \atop {-(7h+5p=249)}} \right. \\\\-2h=-24

Divide both sides by -2:

-2h/-2 = -24/-2

h = 12

There were 12 hardcover copies sold.

Substitute this into our first equation:

12+p=45

Subtract 12 from each side:

12+p-12 = 45-12

p = 33

There were 33 paperback copies sold.

3 0
4 years ago
Read 2 more answers
Can somebody please help me? (PreCalc
andrew-mc [135]
\csc\theta=\dfrac1{\sin\theta}=\dfrac{\sqrt{17}}}4\implies\sin\theta=\dfrac4{\sqrt{17}}

Recall that \sin^2\theta+\cos^2\theta=1, which means

\cos\theta=\pm\sqrt{1-\sin^2\theta}=\pm\sqrt{1-\dfrac{16}{17}}=\pm\dfrac1{\sqrt{17}}

Since \tan\theta=\dfrac{\sin\theta}{\cos\theta}>0, and \sin\theta>0, it follows that \cos\theta>0 too, so you take the positive root:

\cos\theta=\dfrac1{\sqrt{17}}

Therefore

\cot\theta=\dfrac{\cos\theta}{\sin\theta}=\dfrac{\frac1{\sqrt{17}}}{\frac4{\sqrt{17}}}=\dfrac14
8 0
4 years ago
Given that f(x) = x2 - 13 and g(x) = 5 - x, find (f-9)(10), if it exists.
rosijanka [135]

Answer:

the value for f-9 (10) doesn't exist

6 0
3 years ago
How do you convert to radians
Elanso [62]
 If x is an which of the following statements adds 5 to the current value of x and stores the new value back in x?If x is an int, which of the following statements adds 5 to the current value
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3 years ago
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