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ExtremeBDS [4]
3 years ago
8

What’s the percentage as a decimal

Mathematics
1 answer:
Elenna [48]3 years ago
6 0

Answer:

0.0006

Step-by-step explanation:

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If the minimum payment on a credit card is 3% of the balance, write and equation that would find the minimum payment if the bala
Molodets [167]
Minimum payment
= 3% of $1240
= 3/100 x 1340
= $40.20

3 0
3 years ago
Can someone please tell me how to solve this?
beks73 [17]

Because this is an expression, you cannot solve for a value of x.

3x + 96

We can factor a 3 out of this to simplify it further.

3(x + 32) is the simplified form of the given expression.

5 0
3 years ago
Rewrite 4 1/2=2 <br> please
Luda [366]

The logarithmic expression of 4^(1/2) = 2 is \log_4(2) = \frac 12

<h3>How to rewrite the expression?</h3>

The expression is given as:

4^(1/2) = 2

Take the logarithm of both sides

log(4^(1/2)) = log(2)

Apply the change of base rule

1/2log(4) = log(2)

Divide both sides by log(4)

1/2 = log(2)/log(4)

Change the base

\frac 12 =\log_4(2)

Rewrite as:

\log_4(2) = \frac 12

Hence, the logarithmic expression of 4^(1/2) = 2 is \log_4(2) = \frac 12

Read more about logarithmic expression at:

brainly.com/question/24211708

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8 0
2 years ago
According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women
blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : P(X=r) =^nC_r p^r q^{n-r}

At x = 2

P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}

P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}

P(X=2) =8.8009 \times 10^{-7}

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So,  P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}

 P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})

P(X=r) =9.9439 \times 10^{-6}

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=0.2360

8 0
3 years ago
Lindsey and Will have online account for buying music. Lindsay's account is -$20 and Will's account balance is -$15. Express eac
kramer
Lindsay's debt is greater. Which is more? $20 or $15? I don't know how to express debt... Sorry.

7 0
3 years ago
Read 2 more answers
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