Please answer this due at 11:59

Mathematics

1 answer:

kotegsom [21]3 years ago

7 0

The correct person is tia and the work is in the picture

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what are the minimum first quartile median third quartile and the maximum of the data set? 9,20,4,18,4,18,20,9

den301095 [7]

Answers
1. Minimum = 4
2. First quartile = 6.5
3. Median = 13.5
4. Third quartile = 19
5. Maximum = 20

Explanation
To calculate the measure of central tendency, you first arrange the set of the data in ascending order.
The set of data given will be;
4, 4, 9, 9, 18, 18, 20, 20.

Part 1:
The minimum value of the data is 4.

Part 2:
The first quatile is the median of the lower half which is comprised by:
4, 4, 9, 9

1st quartile = (4+9)÷2
= 13÷2
= 6.5

Part 3:
Median of the data is;

Median = (9+18)÷2
=27÷2
= 13.5

Part 4:
3rd quartile is the median of the upper half which comprises of;
18, 18, 20, 20.

3rd quartile = (18+20)÷2
= 48÷2
= 19

Part 5
The maximum of the set of data is 20.

7 0

3 years ago

You are given the dollar value of a product in 2015 and the rate at which the value of the product is expected to change during

Charra [1.4K]

Answer:

V = $3.50t + $90.5....

Step-by-step explanation:

V(t) is a function of t that expresses the value in year 2000+t.

We know that the increase is $3.50 times t.

So,

V(t) = $3.50t + c

where c is the constant.

V(15) = $3.50 (15) + c = $143 [t=15 as mentioned in the question]

and therefore

c = $143 - $3.50 (15)

c= $143 - $52.50

c= $90.5

Now we got the value of c. We can write the equation as

V = $3.50t + $90.5....

4 0

3 years ago

Which system has no solution? Check all that appy.

Ainat [17]

The first equation has no solution

The picture shows all the work I did, the reason I took a pic is because it is a little hard to explain by text, but I hope this helped you!