Please answer the above question

1. Solve the system of equations using the linear combination method.

goldfiish [28.3K]

The linear combination method involves multiplying, adding and subtracting in such a way that allows one variable to be eliminated in the addition or subtraction step. This leaves the other variable alone, allowing its value to be determined.

1. 5m+3n=41, 3m−6n=9
Multiply 1st equation by 2: 10m + 6n = 82
Add to 2nd equation: 13m = 91
Divide by 13: m = 7
Substitute back to 1st equation: n = 2
Therefore m = 7 and n = 2.

2. 6g+8h=40 −6g+2h=−20
Add both equations: 10h = 20
Divide by 10: h = 2
Substitute to 1st equation: g = 4
Therefore g = 4 and h = 2.

3. 9x+5y=35 2x+5y=0
Subtract 1st equation by the 2nd equation: 7x = 35
Divide by 7: x = 5
Substitute back to the 1st equation: y = -2
Therefore x = 5 and y = -2.

8 0

4 years ago

Find the volume and surface area of the rectangular solid. The length is 4 meters, the width is 6 meters, and the height is 3 me

Nutka1998 [239]

Answer:

Volume = h * w * l (height, width, length)

Volume = 4* 6 * 3

Volume = 72 cube meters

Surface area is finding the are of every 2D plane on the solid.

2(w * h) + 2(l*h) + 2(w * l)

Surface are = 108 square meters

3 0

3 years ago

Please help! Will give Brainly!

gogolik [260]

Step-by-step explanation:

There are 5280 feet in a mile and 3600 seconds in an hour.

So a truck driving 45 miles an hour would be driving:

$\frac{45 miles}{1 hour}$ x $\frac{1 hour}{3600 seconds}$ x $\frac{5280 feet}{1 mile}$ = $\frac{237600}{3600}$ = 66 feet per seconds

5 0

3 years ago

In RSM camp, there are four counselors for every fifty seven students and three teachers for every five counselors. Chapter Refe

max2010maxim [7]

The number of students attending the camp that summer is 380 students

Step-by-step explanation:

There are four counselors for every fifty seven students

There are three teachers for every five counselors

Ms. Rifkin asked all 16 teachers present at the camp to attend a

teachers meeting

To solve this question we will use the ratio

The given is:

1. 4 counselors for every 57 students

2. 3 teachers for every 5 counselors

3. There are 16 teachers

At first let us find the 16 teachers are for how many counselors

∵ 3 teachers : 5 counselors

∵ 16 teachers : x counselors

∴ $\frac{3}{5}=\frac{16}{x}$

By using cross multiplication

∴ 3x = 16 × 5

∴ 3x = 80

Divide both side by 3

∴ x = $\frac{80}{3}$

Then let us find the $\frac{80}{3}$ counselors are for how many students

∵ 4 counselors : 57 students

∵ $\frac{80}{3}$ counselors : y students

∴ $\frac{4}{57}=\frac{80/3}{y}$

By using cross multiplication

∴ 4y = 57 × $\frac{80}{3}$

∴ 4y = 1520

Divide both sides by 4

∴ y = 380 students

The number of students attending the camp that summer is 380 students

Learn more:

You can learn more about the ratio in brainly.com/question/6952762

#LearnwithBrainly

4 0

3 years ago

Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how

astra-53 [7]

Answer:

When Aria sold her house after eleven years it worth was $95,300.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be $x.$

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

$x=A\times (1+\frac{r}{100})^{11}$

$x=75000\times (1+\frac{2.2}{100})^{11}$

$x=75000\times (1+0.022)^{11}$

$x=75000\times (1.022)^{11}$

$x=75000\times 1.2704$

$x=95280.$

The amount of house after eleven years to the nearest hundred dollars is $95,300.

Therefore, when Aria sold her house after eleven years it worth was $95,300.

3 0

3 years ago

Please answer the above question​

Please answer the above question