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Fudgin [204]
3 years ago
6

Patrick ate 540 apples in 9 hours. at that rate, how many apples could he eat in 4 minutes?

Mathematics
1 answer:
son4ous [18]3 years ago
5 0

Answer:

He could eat 4 apples in 4 minutes

Step-by-step explanation:

If he eats 1 apple per minute (which I dont know how he does) then in 4 minutes he will have eaten 4 apples.

You might be interested in
Need help finding measure of angle R.
Hunter-Best [27]

Answer:

B.) 113°

Step-by-step explanation:

In the isosceles trapezoid, angles T and S are congruent. Find the value of x:

4x+7=7x-38

Subtract 4x from both sides:

4x-4x+7=7x-38-4x\\7=3x-38

Add 38 to both sides:

7+38=3x-38+38\\45=3x

Divide both sides by 3:

\frac{45}{3}=\frac{3x}{3}\\\\  15=x\\\\x=15

x is equal to 15. Now substitute the value of x into the one of the expressions:

4(15)+7\\60+7\\67

or

7(15)-38\\105-38\\67

The angles T and S are 67°.

The angles of a trapezoid will always add up to a total of 360°, so add the angles T and S:

67+67=134

Subtract their total from 360:

360-134=226

The total of the angles Q and R is 226°. Since this is an isosceles trapezoid, those two angles are also congruent. Divide the value by 2:

\frac{226}{2}= 113

Angle R is 113°.

Done.

7 0
3 years ago
George walked on a treadmill 16 ¾ miles over 4 days. How many miles did he walk per day?
elena-s [515]

Answer:

64 3/16 miles

Step-by-step explanation:

Total distance walked = 16 3/4 miles = 67/4 miles (converted to improper fraction to help with division later)

number of days walked = 4 days

Miles walked per day = total distance walked ÷ number of days

= 16 3/4 ÷ 4

= 67/4  ÷ 4

= 67/4 x 1/4

= 67/16

= 64 3/16 miles

8 0
3 years ago
If DE = 37 cm and EF = 16 cm, then what are the possible lengths for DF so that DE,EF, and DF can form a triangle? Explain your
Molodets [167]

Answer:

The length of DF must be between 21 and 53.

Step-by-step explanation:

In a triangle, the length of two sides added together must exceed the length of the 3rd side. So, since EF is the shortest of the two givens, we know that EF + DF must be greater than DE. So we can plug in these numbers to find the minimum.

EF + DF > DE

16 + DF > 37

DF > 21

Now, for the upper maximum, we know that the two given lengths must be greater than the length of DF. So again, we can solve for the maximum using the amounts.

DE + EF > DF

37 + 16 > DF

53 > DF

With these two in mind, we know that DF must be between 21 and 53

6 0
4 years ago
Help Me out please ???
TEA [102]

I suppose that the correct answer could be

2y=7

8 0
3 years ago
Read 2 more answers
What force is exerted on a test charge of 3.25 E−5 C, if it is placed in an electric field of magnitude 1.40 E4 N/C? Remember to
marshall27 [118]

Answer:

0.46 newtons

Step-by-step explanation:

For these kinds of problems, you can employ the formula

E=\dfrac{F}{q}

where E represents the field in N/C, F represents the force in newtons, and q represents the charge in coulombs. You can therefore set up the following equation:

1.4\times 10^4 N/C=\dfrac{F}{3.25\times 10^{-5}C} \\\\

F=(1.4\times 10^4 N/C) \times (3.25 \times 10^{-5} C)=4.6 \times 10^{-1} N (following sig figs)

Hope this helps!

5 0
3 years ago
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