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Alex787 [66]
3 years ago
11

Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how

much was it worth, to the nearest hundred dollars?
Mathematics
1 answer:
astra-53 [7]3 years ago
3 0

Answer:

When Aria sold her house after eleven years it worth was <u>$95,300</u>.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be x.

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

x=A\times (1+\frac{r}{100})^{11}

x=75000\times (1+\frac{2.2}{100})^{11}

x=75000\times (1+0.022)^{11}

x=75000\times (1.022)^{11}

x=75000\times 1.2704

x=95280.

<em>The amount of house after eleven years to the nearest hundred dollars is $95,300.</em>

Therefore, when Aria sold her house after eleven years it worth was $95,300.

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A parachutist falls at a speed of about 12 miles per hour. Find this speed in feet per second
padilas [110]
So in 1 hour, the parachutist will fall 12 miles or
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convert
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6 0
2 years ago
Can y’all plz help and thank you. Aslo hope y’all have a wonderful and beautiful day.
stepan [7]

Answer:

a) Rumble: $1

Pedal: $0.6

b) more than 5 songs

c) No, should be integers only

d) No, has to be integers greater than or equal to 2

Step-by-step explanation:

Part a

Rate per song is the slope.

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Slope is 0.6

Rate is $0.6 per song

Pedal:

Slope: (4-2)/(2-0) = 1

Rate is $1 per song

Part b

Pedal would be a better deal if it's cost is lower than Rumble's

Rumble's cost: C = 2 + S

Pedal's cost: C = 4 + 0.6S

4 + 0.6S < 2 + S

0.4S > 2

S > 5

c) No, because no. of songs has to be positive integers only.

For example graph shows S = 2.5, but we know that's not possible

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cost can't be in decimals either.

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7 0
3 years ago
A woman 5 ft tall walks at the rate of 7.5 ft/sec away from a streetlight that is 10 ft above the ground. At what rate is the ti
lesya [120]
Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
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s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
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From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec. 
8 0
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