Ask question

Ask question

All categories

Ray Of Light [21]

3 years ago

5

How is this possible? Explain and list the two different endpoints.

1 answer:

balandron [24]3 years ago

4 0

Roarrrrtrrtrrrtrt roarrrrtrtt

You might be interested in

A plane travels 236 miles in 1. 4 hours against the wind. On the return trip, it travels the same 236 miles in 1 hour. Find the

KIM [24]

Speed is given by the distance traveled divided by the time spent.

The net speed with which the plane traveled against the wind is given by $\frac{236}{1.4} =168.57\ mi/hr$ while the speed with which the plane travelled in the return trip is given by $\frac{236}{1} =236\ mi/hr$

Let the speed of the plane be v and the speed of the wind be w, then when the plane was traveling against the sun, we have, v - w = 168.57 and when the plane is travelling in the direction of the wind, we have, v + w = 236.

Subtracting the first equation from the second equation, we have: 2w = 236 - 168.57 = 67.43

Thus, w = 67.43 / 2 = 33.715

Therefore, the speed of the wind is approximately 33.7 mi/hr.

5 0

4 years ago

Read 2 more answers

3b – 7 < 32 I don't know the answer help !!

Nuetrik [128]

If your solving for B then its B<43/3

7 0

4 years ago

Read 2 more answers

Select the correct answer.

mash [69]

Answer:

The answer is B because it's all real numbers since it won't stop

Step-by-step explanation:

5 0

3 years ago

Given g(x)=sqrt x-4 and h(x)=2x-8 what is (g(h(10))<br> HELP ME I AM .3 POINTS AWAY FROM PASSING.

Whitepunk [10]

<span><span>The answer (<span>g<span>(x)</span></span>)</span>=x−7</span>

<span><span>g<span>(<span>f<span>(x)</span></span>)</span></span>=<span>√<span><span>x2</span>−7</span></span></span>

Explanation:

Put g inside f to find <span>f<span>(<span>g<span>(x)</span></span>)</span></span>

<span><span>f<span>(x)</span></span>=<span>x2</span>−4</span>

<span><span>g<span>(x)</span></span>=<span>√<span>x−3</span></span></span>

<span><span>f<span>(<span>g<span>(x)</span></span>)</span></span>=<span><span>(<span>√<span>x−3</span></span>)</span>2</span>−4</span>

<span><span>f<span>(<span>g<span>(x)</span></span>)</span></span>=x−3−4</span>

<span><span>f<span>(<span>g<span>(x)</span></span>)</span></span>=x−7</span>

Put f inside g to find <span>g<span>(<span>f<span>(x)</span></span>)</span></span>

<span><span>g<span>(x)</span></span>=<span>√<span>x−3</span></span></span>

<span><span>f<span>(x)</span></span>=<span><span>x2</span>−4</span></span>

<span><span>g<span>(<span>f<span>(x)</span></span>)</span></span>=<span>√<span><span><span>x2</span>−4</span>−3</span></span></span>

<span><span>g<span>(<span>f<span>(x)</span></span>)</span></span>=<span>√<span><span>x2</span>−7</span></span></span>:

The answers are <span><span>f<span>(<span>g<span>(x)</span></span>)</span></span>=x−7</span>
and <span><span>g<span>(<span>f<span>(x)</span></span>)</span></span>=<span>√<span><span>x2</span>−7</span></span></span>

Explanation:

This is a composition of functions.

<span><span>f<span>(x)</span></span>=<span>x2</span>−4</span>

<span><span>g<span>(x)</span></span>=<span>√<span>x−3</span></span></span>

<span>fo<span>g<span>(x)</span></span>=<span>f<span>(<span>g<span>(x)</span></span>)</span></span>=<span>f<span>(<span>√<span>x−3</span></span>)</span></span>=<span><span>(<span>√<span>x−3</span></span>)</span>2</span>−4</span>

<span>=x−3−4=x−7</span>

And

<span>go<span>f<span>(x)</span></span>=<span>g<span>(<span>f<span>(x)</span></span>)</span></span>=<span>g<span>(<span>x2</span>−4)</span></span>=<span>√<span><span>(<span>x2</span>−4)</span>−3</span></span></span>

<span>=<span>√<span><span>x2</span>−4−3</span></span>=<span>√<span><span>x2</span>−7</span></span></span>

You can see that

<span><span>f<span>(<span>g<span>(x)</span></span>)</span></span>≠</span>g(f(x))

7 0

4 years ago

Read 2 more answers

Any athlete who fails the Enormous State University's women's soccer fitness test is automatically dropped from the team. Last y

castortr0y [4]

Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.

Conditional Probability

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.
$P(A \cap B)$ is the probability of both A and B happening.
P(A) is the probability of A happening.

In this problem:

Event A: Fail the test.
Event B: Unfit.

The probability of <u>failing the test</u> is composed by:

46% of 37%(are fit).
100% of 63%(not fit).

Hence:

$P(A) = 0.46(0.37) + 0.63 = 0.8002$

The probability of both failing the test and being unfit is:

$P(A \cap B) = 0.63$

Hence, the conditional probability is:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.63}{0.8002} = 0.7873$

0.7873 = 78.73% probability that Mona was justifiably dropped.

A similar problem is given at brainly.com/question/14398287

3 0

3 years ago