Answer:
There are two x-intercepts.
A quadratic function whose maximum degree two. Therefore, Total two x-intercept possible.
We are given the range of quadratic function y less than equal to 2. It means parabola is downward whose maximum value 2.
Here y is greater than 2 and parabola form downward. Here must be two x-intercept.
If a>0 then form open up parabola.
If a<0 then open down parabola.
Here open down parabola. So, we get total two x-intercept.
Please see the attachment for diagram.
Let's solve this problem step-by-step.
STEP-BY-STEP EXPLANATION:
Let's first establish that triangle BCD is a right-angle triangle.
Therefore, we can use Pythagoras theorem to find BC and solve this problem. Pythagoras theorem is displayed below:
a^2 + b^2 = c^2
Where c = hypotenus of right-angle triangle
Where a and c = other two sides of triangle
Now we can solve the problem by substituting the values from the problem into the Pythagoras theorem as displayed below:
Let a = BC
b = DC = 24
c = DB = 26
a^2 + b^2 = c^2
a^2 + 24^2 = 26^2
a^2 = 26^2 - 24^2
a = square root of ( 26^2 - 24^2 )
a = square root of ( 676 - 576 )
a = square root of ( 100 )
a = 10
Therefore, as a = BC, BC = 10.
If we want to check our answer, we can substitute the value of ( a ) from our answer in conjunction with the values given in the problem into the Pythagoras theorem. If the left-hand side is equivalent to the right-hand side, then the answer must be correct as displayed below:
a = BC = 10
b = DC = 24
c = DB = 26
a^2 + b^2 = c^2
10^2 + 24^2 = 26^2
100 + 576 = 676
676 = 676
FINAL ANSWER:
Therefore, BC is equivalent to 10.
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Answer:
10,000,000
Step-by-step explanation:
ten million
Answer:
Three solutions.
Step-by-step explanation:
In order to solve system of equations by graphical method, we graph the system of equations. The intersection point (s) of the two graph would give us the solution.
If the graph of the equations intersect at 2 points then there will be 2 solutions, if there are 4 intersection then there would be 4 solutions and so on.
For the given graph, we can see that there are three intersection points.
Hence, there would be three solutions.
