How is this possible? Explain and list the two different endpoints.

Mathematics

1 answer:

balandron [24]3 years ago

4 0

Roarrrrtrrtrrrtrt roarrrrtrtt

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Type the correct answer for each.

xxTIMURxx [149]

If point $\left(x,\ \frac{\sqrt{7}}{3}\right)$ is on the unit ircle, then:

$x^2+\left( \frac{ \sqrt{7} }{3} \right)^2=1 \\ \\ \Rightarrow x^2+ \frac{7}{9} =1 \\ \\ \Rightarrow x^2=1- \frac{7}{9} = \frac{2}{9} \\ \\ \Rightarrow x= \sqrt{ \frac{2}{9} } = \frac{ \sqrt{2} }{3}$

Since, the point is in the second quadrant, x is negative.

Thus, $(x,\ y)=\left(x,\ \frac{\sqrt{7}}{3}\right)=\left(-\frac{ \sqrt{2} }{3},\ \frac{\sqrt{7}}{3}\right)$

Part A:

$3 \sqrt{7} =6\left( \frac{ \sqrt{7} }{2} \right) \\ \\ =6\left( \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \right) \\ \\ =6\left( \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } \right)=-6\left( \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } \right) \\ \\ =-6\left( \frac{y}{x} \right)=-6\tan\theta$

Therefore, $-6\tan\theta=3\sqrt{7}$ .

Part B:

$- \frac{ \sqrt{7} }{2} =- \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \\ \\ =- \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } = \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } = \frac{y}{x} \\ \\ =\tan\theta$

Therefore, $\tan\theta=- \frac{ \sqrt{7} }{2}$

8 0

3 years ago

Hey:) can you please help me posted picture of question

mr Goodwill [35]

The top row contains the product of $x^{2}$ with each term of the expressions $x^{6}+ x^{4}+ x^{2}$ and bottom row contains the product of -1 with each term of expression $x^{6}+ x^{4}+ x^{2}$ .

The final result will be the sum of terms of both rows as shown below:

$( x^{6}+ x^{4} + x^{2} )( x^{2} -1) \\ \\ 
= x^{2} ( x^{6}+ x^{4} + x^{2} )-1( x^{6}+ x^{4} + x^{2} ) \\ \\ 
= x^{8}+ x^{6}+ x^{4}- x^{6}- x^{4}- x^{2} \\ \\ 
= x^{8}- x^{2}$

So the correct answer is option D

8 0

3 years ago

A point is randomly chosen in the diagram shown below.

Alex73 [517]

D it is unlikely hope it helps

5 0

3 years ago

Read 2 more answers

Find the slope of the line drawn below

Marysya12 [62]

Answer:

slope is undefined