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NeX [460]
3 years ago
15

Write as an exponent with the base of b:

title="(b^{4} )^{m}" alt="(b^{4} )^{m}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
natali 33 [55]3 years ago
4 0

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{b}^{4 \times m}  =  {b}^{4m}

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

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Does anyone know how to Graph f(x)=51(2)^x
3241004551 [841]
This is an exponential function.   

If x = 0, 2^x = 2^0 = 1.  The beginning value of 2^x is 1 and the beginning value of 51*2^x is 51.

Make a table and graph the points:

x        y=51*2^x                                point (x,y)
--       ---------------                            ---------------
0             51                                       (0,51)
2            51*2^2 = 51(4) = 204           (2,204)             and so on.

The graph shows up in both Quadrants I and II.  Its y-intercept is (0,51).  Its slope is always positive.

5 0
3 years ago
Read 2 more answers
What is the quadratic formula in vertex form?
telo118 [61]

Answer:

See explanation below to use the vertex form to solve a quadratic equation.

Step-by-step explanation:

(x - h)^2 - k = 0, the vertex is (h, -k)

An example below, taking a quadratic equation and completing the square:

x^2 - 2x - 1 = 0

x^2 - 2x = 1

(-2/-2)^2 = 1, add 1 to both sides of the equation.

x^2 - 2x + 1 = 1 + 1

(x - 1)^2 = 2

(x - 1)^2 - 2 = 0

The vertex is (1, -2)

8 0
3 years ago
Solve the equation. Round the answer to the nearest tenth.
VMariaS [17]
1,04x+3,14=7,98\ \ \  \ \ | subtract\ 3,14\\\\
1,04x=4,84\\\\
x\approx4,7
5 0
3 years ago
Find 94% of 90! Do not round your awnser. Show your work​
Katen [24]
The answer would be 84.6

You multiply 94 and 90 and then add a decimal point since you can’t go over 90.

That’s how I do it mentally.
4 0
3 years ago
H (x) =4x-2 complete the function table
Helen [10]

<em>Note: </em>

<em>You did not mention the table of the points. But, I would try to clear your concept by taking 6 sample points.</em>

Answer:

The table and the graph of the function h(x) = 4x-2 is also attached below.

Step-by-step explanation:

Given the function

h(x) = 4x-2

substituting x = 0 in the function

h(0) = 4(0) -2 = 0 -2 = -2

Therefore, the point (0, -2) satisfies on the function.

substituting y = 1 in the function

h(1) = 4(1) -2 = 4 -2 = 2

Therefore, the point (1, 2) satisfies on the function.

substituting y = 2 in the function

h(2) = 4(2) -2 = 8 -2 = 6

Therefore, the point (2, 6) satisfies on the function.

substituting y = 3 in the function

h(3) = 4(3) -2 = 12 -2 = 10

Therefore, the point (3, 10) satisfies on the function.

substituting y = 4 in the function

h(4) = 4(4) -2 = 16 -2 = 14

Therefore, the point (4, 14) satisfies on the function.

substituting y = 5 in the function

h(5) = 4(5) -2 = 20 -2 = 18

Therefore, the point (5, 18) satisfies on the function.

Therefore, we conclude that table:

x                  h(x) = 4x-2

0                  -2

1                    2

2                   6

3                   10

4                   14

5                   18

The graph of the function h(x) = 4x-2 is also attached below.

5 0
3 years ago
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