Question

Find an equation of the line passing through the points (−8,2) with the slope m= 4/3

Answer 1

Answer:

$y=\frac{4}{3}x+\frac{38}{3}$

Step-by-step explanation:

So we want to find an equation of a line passing through (-8,2) with a slope of 4/3.

To do so, we can use the point-slope form. This is:

$y-y_1=m(x-x_1)$

So, substitute (-8,2) for x₁ and y₁, and let m be 4/3:

$y-2=\frac{4}{3}(x+8)$

Distribute the right:

$y-2=\frac{4}{3}x+\frac{32}{3}$

Add 2 to both sides. Note that 2 can be written as 6/3. Thus:

$y=\frac{4}{3}x+\frac{32}{3}+\frac{6}{3}$

Simplify:

$y=\frac{4}{3}x+\frac{38}{3}$

And this is our equation :)