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butalik [34]
3 years ago
12

Juan owes his cousin, Benito, $10.00. Benito is tired of waiting for Juan to pay him back. To try and get Juan to pay up more qu

ickly, Benito has decided to add $1.00 per day to the amount Juan owes him. Juan also owes his brother, Tavon, $15.00. Tavon liked Benito's idea of charging additional money, but because he is Juan's brother, decided he would only charge $.50 per day. Write and solve an equation that shows the number of days it will take for Juan to owe Benito and Tavon the same amount of money.

Mathematics
2 answers:
Mila [183]3 years ago
8 0

Answer:

Hope this will help you :)

Step-by-step explanation:

Gemiola [76]3 years ago
3 0

Answer:

wat???

Step-by-step explanation:

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6 0
2 years ago
Drag the tiles to the correct boxes to complete the pairs.
nevsk [136]

Answer: this is the order from top to bottom.

5

4

6

3. That's youre answer bud. Mark me brainliest if you want.

Step-by-step explanation:

7 0
3 years ago
(question 4 only plz)
Hatshy [7]
#4
White block(s) = 2
Red block(s) = 1
Purple block(s) = 3
Total = 2 +1 + 3 = 6 blocks

a) P(white) = \frac{2}{6} = \frac{1}{3}
    P(red) = \frac{1}{6}
    P(purple) = \frac{3}{6} =  \frac{1}{2}

b)Not white block:
   1 - \frac{1}{3}   OR   \frac{1}{2} + \frac{1}{6}
    \frac{2}{3}                 \frac{2}{3}
Because, when they say no white blocks, we simply do not count them and add the rest to find that probability without white blocks.

c) The probability stays the same: lets say now we have
4 white blocks, 2 red, and 6 purple, total will be 12

P(white)=\frac{4}{12} which is still \frac{1}{3}

d) We get two more blocks in the numerator: lets say we have 4 white blocks, 3 red, 5 purple (after adding 2 of each color), total will be 12

P(purple)=\frac{5}{12}
(im not quite sure if my explanation here helps you though)

e) 1 more of white and purple, 5 more of red
  white = 3, purple = 4, red = 6, total = 12
(you can either add 2 to white or purple but make sure you add 5 of red)

P(red)=\frac{6}{12} = \frac{1}{2}
  


5 0
3 years ago
Find the zeros (roots) of the following equations. f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
Talja [164]
Hi,
f(1)=2*1^5-9*1^4+12*1^3-12*1^2+10*1-3\\
=2-9+12-12+10-3\\
=0\\

f(x)=(x-1)(2x^4-7x^3+5x^2-7x+3)\\


g(x)=2x^4-7x^3+5x^2-7x+3\\

g(3)=2*3^4-7*3^3+5*3^2-7*3+3\\
=162-189+45-21+3\\
=0\\

g(x)=(x-3)(2x^3-x^2+2x-1)\\

h(x)=2x^3-x^2+2x-1\\

h( \dfrac{1}{2} )=2* \dfrac{1}{8} - \dfrac{1} {4}+1-1\\
=0\\

h(x)=(2x-1)(x^2+1)\\


f(x)=(x-1)(x-3)(2x-1)(x+i)(x-i)\\



Roots are 1,3,0.5,i,-i.

8 0
3 years ago
Definition of a parrellegram
oksano4ka [1.4K]
A parallelogram is a four-sided figure with opposite sides parallel.
5 0
3 years ago
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