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butalik [34]
2 years ago
12

Juan owes his cousin, Benito, $10.00. Benito is tired of waiting for Juan to pay him back. To try and get Juan to pay up more qu

ickly, Benito has decided to add $1.00 per day to the amount Juan owes him. Juan also owes his brother, Tavon, $15.00. Tavon liked Benito's idea of charging additional money, but because he is Juan's brother, decided he would only charge $.50 per day. Write and solve an equation that shows the number of days it will take for Juan to owe Benito and Tavon the same amount of money.

Mathematics
2 answers:
Mila [183]2 years ago
8 0

Answer:

Hope this will help you :)

Step-by-step explanation:

Gemiola [76]2 years ago
3 0

Answer:

wat???

Step-by-step explanation:

You might be interested in
The sum of Joy's age and her brother's age is 24. Joy's brother's age is 3 years older than twice joy's age. What is the differe
enyata [817]
Let Joy be x years old

<span>Joy's brother's age is 3 years older than twice joy's age.
</span>Joy's Brother = 2x + 3

<span>The sum of Joy's age and her brother's age is 24.
x + 2x + 3 = 24
3x + 3 = 24
3x = 24 - 3
3x = 21
x = 21 </span>÷ 3 
x = 7

Joy:
x = 7

Brother:
2x + 3 = 2(7) + 3 = 17

Difference in their age = 17 - 7 = 10 years

They are 10 years apart.
3 0
3 years ago
Determine if the columns of the matrix form a linearly independent set. Justify your answer. [Start 3 By 4 Matrix 1st Row 1st Co
Volgvan

Answer:

Linearly Dependent for not all scalars are null.

Step-by-step explanation:

Hi there!

1)When we have vectors like v_{1},v_{2},v_{3}, ... we call them linearly dependent if we have scalars a_{1},a_{2},a_{3},... as scalar coefficients of those vectors, and not all are null and their sum is equal to zero.

a_{1}\vec{v_{1}}+a_{2}\vec{v_{2}}+a_{3}\vec{v_{3}}+...a_{m}\vec{v_{m}}=0  

When all scalar coefficients are equal to zero, we can call them linearly independent

2)  Now let's examine the Matrix given:

\begin{bmatrix}1 &-2  &2  &3 \\ -2 & 4 & -4 &3 \\ 0&1  &-1  & 4\end{bmatrix}

So each column of this Matrix is a vector. So we can write them as:

\vec{v_{1}}=\left \langle 1,-2,1 \right \rangle,\vec{v_{2}}=\left \langle -2,4,-1 \right \rangle,\vec{v_{3}}=\left \langle 2,-4,4 \right \rangle\vec{v_{4}}=\left \langle 3,3,4 \right \rangle Or

Now let's rewrite it as a system of equations:

a_{1}\begin{bmatrix}1\\ -2\\ 0\end{bmatrix}+a_{2}\begin{bmatrix}-2\\ 4\\ 1\end{bmatrix}+a_{3}\begin{bmatrix}2\\ -4\\ -1\end{bmatrix}+a_{4}\begin{bmatrix}3\\ 3\\ 4\end{bmatrix}=\begin{bmatrix}0\\ 0\\ 0\end{bmatrix}

2.1) Since we want to try whether they are linearly independent, or dependent we'll rewrite as a Linear system so that we can find their scalar coefficients, whether all or not all are null.

Using the Gaussian Elimination Method, augmenting the matrix, then proceeding the calculations, we can see that not all scalars are equal to zero. Then it is Linearly Dependent.

 \left ( \left.\begin{matrix}1 &-2  &2  &3 \\ -2 &4  &-4  &3 \\ 0 & 1 &-1  &4 \\ \end{matrix}\right|\begin{matrix}0\\ 0\\ 0\end{matrix} \right )R_{1}\times2 +R_{2}\rightarrow R_{2}\left ( \left.\begin{matrix}1 &-2  &2  &3 \\ 0 &0 &9  &0\\ 0 & 1 &-1  &4 \\ \end{matrix}\right|\begin{matrix}0\\ 0\\ 0\end{matrix} \right )\ R_{2}\Leftrightarrow  R_{3}\left ( \left.\begin{matrix}1 &-2  &2  &3 \\ 0 &1  &-1  &4 \\ 0 &0 &9  &0 \\ \end{matrix}\right|\begin{matrix}0\\ 0\\ 0\end{matrix} \right )\left\{\begin{matrix}1a_{1} &-2a_{2}  &+2a_{3}  &+3a_{4}  &=0 \\  &1a_{2}  &-1a_{3} &+4a_{4}  &=0 \\  &  &  &9a_{4}  &=0 \end{matrix}\right.\Rightarrow a_{1}=0, a_{2}=a_{3},a_{4}=0

S=\begin{bmatrix}0\\ a_{3}\\ a_{3}\\ 0\end{bmatrix}

3 0
3 years ago
I need a lot of help with this problem lol. I need help finding the mean, median, mode, and range for the numbers .06, 1.10, .75
son4ous [18]

Answer:

mean = 0.76

median = 0.75

range = 1.79

Step-by-step explanation:

mean = sum/no of items

for media they need to be sorted: 0.05,0.06,0.75,1.10,1.84

median is the middle item, so 0.75

range = largest item - smallest item = 1.84 - 0.05 = 1.79

3 0
2 years ago
What is the value of x<br> -2 = 2x
Lemur [1.5K]
Divide both sides by negative two
the answer is x = -1
8 0
3 years ago
Read 2 more answers
Number one I am really stuck with can you please help me
Tom [10]
77 - 2 = 75

75 ÷ 5 = 15

The number is 15.

Hope this helped!
3 0
3 years ago
Read 2 more answers
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