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r-ruslan [8.4K]
3 years ago
15

Donna wants to calculate the height of a tree. She finds the length of the tree's shadow is 25 meters and the angle of elevation

from the ground to the top of the tree is 30°. Find the height of the tree to the nearest whole number.

Mathematics
1 answer:
nadezda [96]3 years ago
4 0

Answer:55

Step-by-step explanation:

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My car cost 3500 I get paid 300 a week how long will it be until I get the car
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It should be about 12 weeks
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What ordered pair is a solution to this equation 4x+y=20
Ahat [919]

Answer:

happy holidays!!!!!!!! love you u are strong and a true buddy

Step-by-step explanation:

3 0
3 years ago
**For this question: you just have to come up w/ an equation.
QveST [7]
There's two actually.
0.25q + 0.10d = 3.85
q + d = 25
5 0
4 years ago
What is the opppsite of 1 1/3
marin [14]

Answer:

find below

Step-by-step explanation:

it would either be -1 1/3 or -3/4 since that is the reciprocal of -1 1/3

7 0
3 years ago
Let $M$ be the least common multiple of $1, 2, \ldots, 20$. How many positive divisors does $M$ have
Veronika [31]

Consider the prime factorization of 20!.

20! = 20 \times 19 \times 18 \times \cdots \times 3 \times 2 \times 1

The LCM of 1, 2, ..., 20 must contain all the primes less than 20 in its factorization, so

M = 2 \times 3 \times 5 \times 7 \times 11 \times 13 \times 17 \times 19 \times m

where m is some integer not divisible by any of these primes.

Compare the factorizations of the remaining divisors of 20!, and check off any whose factorizations are already contained in the product of primes above.

4 = 2^2 - missing a factor of 2

6 = 2\times3 - ✓

8 = 2^3 - missing a factor of 2²

9 = 3^2 - missing a factor of 3

10 = 2\times5 - ✓

12 = 2^2\times3 - missing a factor of 2

14 = 2\times7 - ✓

15 = 3\times5 - ✓

16 = 2^4 - missing a factor of 2³

18 = 2\times3^2 - missing a factor of 3

20 = 2^2\times5 - missing a factor of 2

From the divisors marked "missing", we add the necessary missing factors to the factorization of M, so that

M = 2 \times 3 \times 5 \times 7 \times 11 \times 13 \times 17 \times 19 \times 2^3 \times 3

Then the LCM of 1, 2, 3, …, 20 is

M = 2^4 \times 3^2 \times 5 \times7 \times 11 \times 13 \times17 \times 19

\implies \boxed{M = 232,792,560}

3 0
2 years ago
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