i'm sorry but can you put in more details as to what each item costs, if it is just variables then it should be something like b times the amount bought plus c times the amount bought. without the costs i cannot actually give you how much she spent
A
Plug the values in and check
Mark brainliest please
Answer:
option D
Step-by-step explanation:
Jerry solved this equation:

In the first step , she multiplied 3 inside the parenthesis
1. 
In step 2, 3/4 is added on both sides
2. 
In step 3, we take LCD 12
3. 
In step 4, add the fractions
4. 
Here, 3 or 3/1 are same.

In step 5, to remove 3/1 we multiply both sides by 1/3.
Instead of multiplying 1/3 , Jerry made an error by multiplying 3/1


In step 5, he should have multiplied both sides by 1/3
Upper Tolerance
Remark
The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.
Solution
<u>Upper Limit</u>

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

Which results in

With a final result for the fractions of 45/64
So the upper tolerance = 3 45/64
<u>Lower Tolerance</u>
Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

Your answer should be 3 and 43/64
First we need to count the total number scores. This can be done from the stem and leaf plot. The total number of scores are 19. The total number of values is odd, so the median position will be:

Thus the 10th score is the median score for the class of Mr. Robert. The 10th score from the stem and leaf plot is 81.
Thus 81 is the median score of Mr. Robert's Class.