Answer:
liar is 10
Step-by-step explanation:
Answer:
A) 0.303
The probability that a randomly selected student from the class has brown eyes , given they are male

Step-by-step explanation:
<u>Explanation</u>:-
Given data
Brown Blue Hazel Green
Females 13 4 6 9
Males 10 2 9 12
<em>Let 'B' be the event of brown eyes </em>
<em>Total number of males n(M) = 33</em>
Let B/M be the event of randomly selected student from the class has brown eyes given they are male
<em>The probability that a randomly selected student from the class has brown eyes , given they are male</em>
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<em>From table the brown eyes from males = 10</em>


<u>Final answer</u>:-
The probability that a randomly selected student from the class has brown eyes , given they are male

Answer:
SAS is the answer in my opinion
<span>K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed. WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again.</span>
Formula- A = π r²
a= area
r= radius
diameter of the circle- 3.75 x 2 = 7.5
hope this helps :)