Answer:
Your question is a little unclear. If you are just trying to factor x² + 121, it's prime. (can't be factored using real numbers).
Step-by-step explanation:
The difference of two squares is a special form. a² - b² = (a+b)(a-b).
But, the sum of two squares is prime. a²+ b² cannot be factored.
1st term = n
2nd term = n+1
3rd term = n+2
4th term = n+3
The fifth term in the sequence would be n + 4.
For the fifth term in the sequence a = 3(n+4) - 2.
This should get you started.
Hey there!
First reduce the expression and then cancel the common factors.
2
Hope this helps!
Answer:
x = 9
x = 2
Step-by-step explanation:
