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icang [17]
3 years ago
7

Translate and solve: 3x less than 2 times the sum of 2x and 1 is equal to the sum of 2 and 5. X=

Mathematics
1 answer:
Sauron [17]3 years ago
6 0

Answer:

3 x = 2 = 2 x = 1 = 2 = 5 X =

Step-by-step explanation:

Use the given functions to set up and simplify

5X.

im pretty sure this is right, butt if its not im sorry <3

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What does 34 12/27-19 5/6=
Lunna [17]
<span>34 12/27-19 5/6
</span>You may get common denominators. 

12*2 = 24
27*2 = 54

5*9=45
6*9 = 54

34 24/54 - 19 45/54 
Subtract 19.
15 24/54 - 45/54 
14 33/54 = Answer.
4 0
3 years ago
Read 2 more answers
QUESTION 7<br> Solve for x.<br> (3x + 32)<br> (5x-8)<br> O a. 3<br> b. 12<br> O c. 20<br> O d. 19.5
Alchen [17]

Answer:

The answer is x = 20

Step-by-step explanation:

If you set both equations equal to each other and solve for x, you will get 20.

3x+32 = 5x-8        add 8 to both sides

3x+40 = 5x           subtract 3x from both sides

40 = 2x                 divide by 2 on both sides

20 = x

7 0
3 years ago
Which of the following expressions is this one equivalent to?
padilas [110]

Hello from MrBillDoesMath!

Answer:

Choice D,  x-2


Discussion:

Observe the the highest order term in the numerator is  x^4 and the highest order term in the denominator is x^3. So the highest order term in their quotient is x^4/x^3 = x.  Choice D is the only possible answer as all other choices start with x^2

Regards,  

MrB

6 0
3 years ago
In the figure, TP and TS are opposite rays. TQ bisects &lt; RTP.
Ket [755]

Answer:

search-icon-image

Class 9

>>Maths

>>Quadrilaterals

>>Quadrilaterals and Their Various Types

>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2

Question

Bookmark

In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28

0

and ∠QRT=65

0

, then find the values of x and y.

463685

expand

Medium

Solution

verified

Verified by Toppr

Given, PQ⊥PS,PQ∥SR,∠SQR=28

∘

,∠QRT=65

∘

According to the question,

x+∠SQR=∠QRT (Alternate angles as QR is transversal.)

⇒x+28

∘

=65

∘

⇒x=37

∘

Also ∠QSR=x

⇒∠QSR=37

∘

Also ∠QRS+∠QRT=180

∘

(Linear pair)

⇒∠QRS+65

∘

=180

∘

⇒∠QRS=115

∘

Now, ∠P+∠Q+∠R+∠S=360

∘

(Sum of the angles in a quadrilateral.)

⇒90

∘

+65

∘

+115

∘

+∠S=360

∘

⇒270

∘

+y+∠QSR=360

∘

⇒270

∘

+y+37

∘

=360

∘

⇒307

∘

+y=360

∘

⇒y=53

∘

Step-by-step explanation:

please mark me as brainlist please

6 0
2 years ago
Leila says that 75% of a number will always be greater than 50% of any other number. Complete one inequality to support Leilas c
Greeley [361]
If a number is positive, Leila's theory that 75% of a number will always be greater than 50% of another number is <em>true</em>;<em> </em>however, if both numbers are negative, or if the number of which she finds 50% is much greater than the number of which she finds 75%, Leila's theory could be incorrect.

This inequality shows that Leila is correct: 100(0.75) \geq 50(0.50) (which simplifies to 75 \geq 25)

This inequality shows that Leila is incorrect: 50(0.75) \geq 100(0.50) (which simplifies to 37.5 \geq 50)

Hope this helps!
6 0
3 years ago
Read 2 more answers
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