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Aneli [31]
3 years ago
11

Can someone please help

Mathematics
2 answers:
ollegr [7]3 years ago
8 0

-18x

you first times the numbers, which becomes -18

Next you add the exponent from the veriables (x) (if you're diving you're subtractiong example: x^a/x^b = x^a-b)

Sooo when you add them you get 8-7=1 which means.. x^1 (but you don't need to put the 1)

-18x

Savatey [412]3 years ago
4 0

Answer: Select the first one

Step-by-step explanation:

-6 multiplied 3 is -18

AND they both have power x which means  -6x⁸   multiply 3x ⁻⁷

                                                         =  -18 x⁸ ⁺⁽⁻⁷ ⁾(As the have same variable )

                                                         =  -18 x⁸⁻⁷

                                                           =-18 x

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Using the order of operations, what should be done first to evaluate (-2)^3 + 4 / (-15 + 9)(3) - 4
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Answer:

A. add -15 and 9

Step-by-step explanation:

We follow the PEMDAS rule as the order of operations to evaluate expressions.

P-Parenthesis

E-Exponents

M-Multiplication

D-Division

A-Addition

S-Subtraction

Given expression : (-2)^3+4\div(-15+9)(3)-4

In order to evaluate the expression, the first step would be to do the parenthesis operations which requires to add -15 and 9.

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Find the probability of rolling an odd sum or a sum less than 7 when a pair of dice is rolled
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Answer:

For the pairs that satisfy that the sum is less than 7 we have:

(1,1) (2,1) (1,2) (3,1) (2,2) (1,3) (4,1) (3,2) (2,3) (1,4) (5,1) (4.2) (3,3) (2,4) (1,5)

So we have a total of 15 pairs where the sum is less than 7

And for an odd sum we have the following pairs

(2,1) (1,2) (4,1) (3,2) (2,3) (1,4) (6,2) (5,2) (4,3) (3,4) (2,5) (1,6) (6,3) (5,4) (4,5) (3,6) (6,5) (5,6)

A total of 18 pairs and we have 6 pairs who are in both cases for the sum less than 7 and the sum an odd number that represent the intersection and using the total probability rule we got:

P = \frac{15+18-6}{36}= \frac{27}{33}= 0.818

Step-by-step explanation:

For this case when a pair of dice is rolled we have the following sample pace for the outcomes:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

We see 36 possible outcomes and we want to find how many of these pairs we got rolling an odd sum or a sum less than 7

For the pairs that satisfy that the sum is less than 7 we have:

(1,1) (2,1) (1,2) (3,1) (2,2) (1,3) (4,1) (3,2) (2,3) (1,4) (5,1) (4.2) (3,3) (2,4) (1,5)

So we have a total of 15 pairs where the sum is less than 7

And for an odd sum we have the following pairs

(2,1) (1,2) (4,1) (3,2) (2,3) (1,4) (6,2) (5,2) (4,3) (3,4) (2,5) (1,6) (6,3) (5,4) (4,5) (3,6) (6,5) (5,6)

A total of 18 pairs and we have 6 pairs who are in both cases for the sum less than 7 and the sum an odd number that represent the intersection and using the total probability rule we got:

P = \frac{15+18-6}{36}= \frac{27}{33}= 0.818

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