Answer:
1.16666666667
Step-by-step explanation:
have a nice day:)
The line y = mx + c has a slope of m.
Parallel line:
A parallel line will also have a slope of m, and should be of the form
y = mx + k
Because the line passes through the point (a,b), therefore
ma + k = b
k = b - ma
The equation of a parallel line is
y = mx + b - ma
= m(x-a) + b
Perpendicular line:
A perpendicular line will have a slope of -1/m, because the product of slopes should be -1.
The equation for a perpendicular line is of the form
y = -(1/m)x + k
Because the line passes through (a,b), therefore
-(1/m)a + k = b
k = b + a/m
The equation for a perpendicular line is
y = -(x/m) + b + a/m
= -(1/m)(x-a) + b
Answer:
Parallel line:
![y=m(x-a)+b](https://tex.z-dn.net/?f=y%3Dm%28x-a%29%2Bb)
Perpendicular line:
He only multiplied 6 by 5, and forgot the r to get 30+r=96. The correct solution is 30 + 6r = 96, or 6r=66. Divide both sides by 6 to get r = 11.
Answer:
Volumetric flow rate = ![v=0.1232 m^3 /s](https://tex.z-dn.net/?f=v%3D0.1232%20m%5E3%20%2Fs)
Step-by-step explanation:
The volumetric flow rate v= area x velocity
from the given data we will find out area and velocity first.
Area = A = (π /4) d^2
Diameter = d = 15 cm = 0.15 m
Area = A = ![(3.14/4) * 0.15^2\\Area = A =0.0176 m^2](https://tex.z-dn.net/?f=%283.14%2F4%29%20%2A%200.15%5E2%5C%5CArea%20%3D%20A%20%3D0.0176%20m%5E2)
The velocity = V = ![\sqrt{2gH}](https://tex.z-dn.net/?f=%5Csqrt%7B2gH%7D)
height of wine in the tank = H = 2.5 m
![Velocity = V = \sqrt{2*9.8*2.5}\\Velocity = V = 7 m/s\\](https://tex.z-dn.net/?f=Velocity%20%3D%20V%20%3D%20%5Csqrt%7B2%2A9.8%2A2.5%7D%5C%5CVelocity%20%3D%20V%20%3D%207%20m%2Fs%5C%5C)
Now calculating the volumetric flow rate
v = A x V
v = 0.0176 x 7
![v=0.1232 m^3 /s](https://tex.z-dn.net/?f=v%3D0.1232%20m%5E3%20%2Fs)