Answer:
Step-by-step explanation:
y= 3.50m + 35
y= 4.25m
4.25m = 3.50m + 35
.75m = 35
m = about 47 movies
Given :
In the early spring, the trout at Big Blue Lake swim at a depth of 30 feet below sea level.
When the lake warms up in the summer, the trout swim 20 feet deeper than that , d = 20 feet .
To Find :
At what position relative to sea level do the trout swim in the summer.
Solution :
Depth in spring from surface ,
.
Let , depth in summer is D .
Now , depth in summer relative to sea-level is :
![D=D_s+d\\\\D=30+20\ feet\\\\D=50\ feet](https://tex.z-dn.net/?f=D%3DD_s%2Bd%5C%5C%5C%5CD%3D30%2B20%5C%20feet%5C%5C%5C%5CD%3D50%5C%20feet)
Therefore , trout swim 50 feet deep below the sea level in the summer .
Hence , this is the required solution .
The expression for doubling a number n and dividing by 3 is 2n/3.
Answer:
The answer is 0.75 and 75%
Answer:
d = 32.73°
Step-by-step explanation:
Angle 'd' is an exterior angle of the given polygon.
By the property of the exterior angles of a polygon, sum of exterior angles of a polygon is 360°.
And the measure of an exterior angle of a polygon = ![\frac{360}{n}](https://tex.z-dn.net/?f=%5Cfrac%7B360%7D%7Bn%7D)
Here 'n' = Number of sides of the polygon
From the picture attached,
Number of exterior angles of the regular polygon = 11
Therefore, measure of the exterior angle = ![\frac{360}{11}](https://tex.z-dn.net/?f=%5Cfrac%7B360%7D%7B11%7D)
= 32.7272
≈ 32.73°