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3 years ago

If 9th term ofap is 99 and 99th term is 9 which term is zero]

Mathematics

1 answer:

Viktor [21]3 years ago

3 0

Answer:

108 th term is zero

Step-by-step explanation:

The nth term of an AP is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₉ = 99 and a₉₉ = 9 then

a₁ + 8d = 99 → (1)

a₁ + 98d = 9 → (2)

Subtract (1) from (2) term by term to eliminate a₁

0 + 90d = - 90

90d = - 90 ( divide both sides by 90 )

d = - 1

Substitute d = - 1 into (1) for value of a₁

a₁ + 8(- 1) = 99

a₁ - 8 = 99 ( add 8 to both sides )

a₁ = 107

Then

107 - (n - 1) = 0

107 - n + 1 = 0

- n + 108 = 0 ( subtract 108 from both sides )

- n = - 108 ( multiply both sides by - 1 )

n = 108

The 108th term is zero

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I need to know the answer please help! and thank you!

Snowcat [4.5K]

Answer:

v/2

Step-by-step explanation:

First, if we expand the expression we know that it is equal to (4/8)*(v^3/v^2)

We can simplify the numbers to get (1/2)*(v^3/v^2)

We know that division of exponents is just subtraction of them, so v³/v² = v^(3-2) = v^1 = v

So, the answer is 1/2 * v or v/2

I hope this helps!

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3 years ago

Can someone help me ASAP

Len [333]

Answer:

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3 years ago

A. Student GPAs: Bob’s z-score z = + 1.71 μ = 2.98 σ = 0.36 b. Weekly work hours: Sarah’s z-score z = + 1.18 μ = 21.6 σ = 7.1 c.

hjlf

Answer:

a) $x = \mu +z*\sigma$

And replacing we got:

$x= 2.98 + 1.71*0.36 = 3.5956$

b) $x = \mu +z*\sigma$

And replacing we got:

$x= 21.6 + 1.18*7.1 = 29.978$

c) $x = \mu -z*\sigma$

And replacing we got:

$x= 150 - 1.35*40= 96$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable of interest for this case. We define the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

And for this case we know that $z = 1.71, \mu = 2.98,\sigma = 0.36$

If we solve for x from the z score formula we got:

$x = \mu +z*\sigma$

And replacing we got:

$x= 2.98 + 1.71*0.36 = 3.5956$

Part b

Let X the random variable of interest for this case. We define the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

And for this case we know that $z = 1.18, \mu = 21.6,\sigma = 7.1$

If we solve for x from the z score formula we got:

$x = \mu +z*\sigma$

And replacing we got:

$x= 21.6 + 1.18*7.1 = 29.978$

Part c

Let X the random variable of interest for this case. We define the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

And for this case we know that $z = -1.35, \mu = 150,\sigma = 40$

If we solve for x from the z score formula we got:

$x = \mu -z*\sigma$

And replacing we got:

$x= 150 - 1.35*40= 96$

5 0

3 years ago

De los 3000 que tenia kristian compro un traje que le costo el 75%¿cuanto le quedo a kristian despues de comprar el traje?

andre [41]

Hola, le quedó $750, espero y si sirva :)

8 0

3 years ago

A town has a population of 17000 and grows at 3% every year. What will be the population after 10 years, to the nearest whole nu

Archy [21]

A=17000(1+.03)^10
A==22,846.58

7 0

4 years ago

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If 9th term ofap is 99 and 99th term is 9 which term is zero]​

If 9th term ofap is 99 and 99th term is 9 which term is zero]