The polynomial is (mx^3+3)(2x²+5x+2)-(8x^5 +20x^4)
if it is reduced to 8x^3+6x²+15x+6, so we can find the value of m
(mx^3+3)(2x²+5x+2)-(8x^5+20x^4) = <span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3+6x²+15x+6-8x^5-20x^4=<span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3=8x^3+6x²+15x+6-6x²-15x-6+ <span>8x^5+20x^4
</span>= 8x^5+20x^4+<span>8x^3= 4(2x^5+5x^4+2x^3)
finally
</span>m(2x^5+5x^4+2x^3)=<span>4(2x^5+5x^4+2x^3), and after simplification
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C: m=4
<span>4. When the expression is factored x²-3x-18 completely,
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one of its factor is x-6
<span>x²-3x-18=0
</span>D= 9-4(-18)= 81, sqrtD=9 x=3-9/2= -6/2= -3, and x=3+9 / 2= 6
so <span>x²-3x-18= (x-6)(x+6)
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This is actually really simple algebra. All you need to know is that Y= Mx + B
and M BEING YOUR SLOPE good luck
We know that the puppy weights 56 ounces and it tells us that 1 pound = 16 ounces so every 16 ounces we have a pound. It wants to know how many pounds does the puppy weights. 56 / 16 = number of pounds. So 56 divided by 16 = pounds. The puppy weights 3.5 pounds
x = 2
solve 4x + 6 = 2x + 10
subtract 2x from both sides
2x + 6 = 10
subtract 6 from both sides
2x = 10 - 6 = 4
divide both sides by 2
x = 
= 2
as a check f(2) =(4 × 2 )+ 6 = 14 and g(2) =( 2× 2) + 10 = 14
