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Alik [6]
3 years ago
15

The length of a rectangle is four times its width. If the perimeter is at most 106 centimeters, what is the greatest possible va

lue for the width? Which inequality models this problem?
A. 2w+2 x (46) _< 106

B. 2w+ 2 x (4) _> 106

C. 2w+2 x (4w) < 106

D. 2w+2 x (46) > 106
Mathematics
2 answers:
andrezito [222]3 years ago
8 0

Answer:

Greatest possible value for the width is 10.6 centimeters.

D. 2w+2 × (46) > 106

Step-by-step explanation:

Perimeter of a rectangle = 2(l + w)

From the given question, P = 106 and l =4w

So that,

  106 = 2(4w + w)

   106 = 2(5w)

   106 = 10 w

      w = 10.6 centimeters

So, the greatest possible value for the width is 10.6 centimeters.

Model;  2w+2 × (46) > 106

      = 2 × 10.6 + 2 × (46)

       = 113.2

113.2 is greater than 106

RideAnS [48]3 years ago
5 0

Answer: A

Step-by-step explanation: The answer is w≤ 13, which means that the greatest value possible is 13.

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Answer:

Multiply the ones. 9 times 83 is 747. Multiply the tens. 30 times 83 is 2,490. Add the products to get 3,237.

The rest of the question:

Which gives the correct order of steps needed to multiply the problem below?   "83x39 "

The steps to multiply  83x39

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2) multiply the tens 30 times 83 = 30 times 3 + 30 times 80 = 90 + 2400 = 2490

3) add 747 and 2490 = 747 + 2490 = 3,237

According to the previous steps, the answer is option 3

Multiply the ones. 9 times 83 is 747. Multiply the tens. 30 times 83 is 2,490. Add the products to get 3,237.

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