Question

The length of a rectangle is four times its width. If the perimeter is at most 106 centimeters, what is the greatest possible value for the width? Which inequality models this problem?
A. 2w+2 x (46) _< 106

B. 2w+ 2 x (4) _> 106

C. 2w+2 x (4w) < 106

D. 2w+2 x (46) > 106

Answer 1

Answer:

Greatest possible value for the width is 10.6 centimeters.

D. 2w+2 × (46) > 106

Step-by-step explanation:

Perimeter of a rectangle = 2(l + w)

From the given question, P = 106 and l =4w

So that,

  106 = 2(4w + w)

   106 = 2(5w)

   106 = 10 w

      w = 10.6 centimeters

So, the greatest possible value for the width is 10.6 centimeters.

Model;  2w+2 × (46) > 106

      = 2 × 10.6 + 2 × (46)

       = 113.2

113.2 is greater than 106

Answer 2

Answer: A

Step-by-step explanation: The answer is w≤ 13, which means that the greatest value possible is 13.