Answer: Well if you were going to think of a circle you can divide it into 4 equal sizes in one of the is equal to two pentagons and a half. If you add all is equal to a loop full of pentagons [which makes 10 pentagons]. Because the ring is made out of regular pentagons, we can work out that each of the interior angles of each pentagon is 108* degrees. By extending the lines that two pentagons share, assuming they will all meet in the middle, it will create a triangle. As we know each angle of a [regular] pentagon is 108* degrees, we know the two base angles of the triangle would equal to 72** which leaves the top angle to be 36 degrees. As [the sum of] angles at a point is 360 degrees, and 36 is divisible by 360, it will make a complete ring. Also, as 360 ÷ 36 = 10, we know that the ring will be made out of 10 pentagons. as formula to calculate the the size of a interior angle of a polygon is (n×180−360)÷n (for n being the number of sides that the polygon has). because the triangle is made by extending the lines, and angles on a line is 180 degrees, 180−108 (an interior angle of a pentagon) =72.
Answer:
The correct option is;
b. Stem and leaf plot
Step-by-step explanation:
A stem-and-leaf plot shows the data shape and the densities of the different classes in a graphical form such that the information in the data such as the data characteristics are self displayed by the data numbers arranged in the stem-and-leaf plot. The stem-and-leaf plot keeps the raw numerical data, in the form they were obtained and by their arrangement, outliers are easily spotted.
Answer:
system 4.
Step-by-step explanation:
3x+6y=9
multiply by 2
6x+12y=18 ....(1)
-2x+-4y=4
multiply by 3
-6x-12y=12 ...(2)
add (1) and (2)
0+0=30
which is impossible .It has no solutions.
x = 16 x sin(60) = 8sqrt(3)
answer is B.
Given :
A bike path is 3 miles long. there are distance markers every path one fourth mile to the end of the path.
To Find :
Which number line correctly models this situation and the total number of distance markers.
Solution :
It is given that their are markers every 1/4 part of mile.
So, their are 4 markers per mile.
Numbers of markers in 3 miles long path is :

Therefore, the total number of distance markers in 3 mile path is 12.
Hence, this is the required solution.