Answer:
The distance between the two airplanes (to the nearest mile) is 1058 miles.
Step-by-step explanation:
An airplane A is at a location 800 miles due west of city X. So AX = 800 miles.
Another airplane is at a distance of 1,200 miles southwest of city X. So BX = 1200 miles.
The angle at city X created by the paths of the two planes moving away from city X measures 60°. So angle ∠AXB = 60°.
In triangle ΔAXB, AX = 800 miles, BX = 1200 miles, ∠AXB = 60°.
Using law of cosines:-
AB² = AX² + BX² - 2 * AX * BX * cos(∠AXB).
AB² = 800² + 1200² - 2 * 800 * 1200 * cos(60°).
AB² = 640000 + 1440000 - 2 * 960000 * 1/2
AB² = 2080000 - 960000
AB² = 1120000
AB = √(1120000) = 1058.300524
Hence, the distance between the two airplanes (to the nearest mile) is 1058 miles.
Answer:
4 × 2 + 20×
Step-by-step explanation:
please your questions are mixed up
Answer: big boi like a someboody 2x -853
Step-by-step explanation:
The question is incomplete. Here is the complete question:
A machine covers 5/8 square foot in 1/4 hour. what is the unit rate?
Answer:
2.5 square feet per hour
Step-by-step explanation:
Given:
Area covered by a machine = 
Time taken to cover the given area = 
Now, unit rate of the first quantity with respect to second quantity is the magnitude of the first quantity being when the second quantity is one unit.
Here, the first quantity is the area covered and the second quantity is the time taken.
So, unit rate is the area covered by the machine in 1 hour.
In order to find that, we use the unitary method and divide the area by the total time taken. Therefore,
Thus, the unit rate is 2.5 square feet per hour.
Answer:
-2/3
Step-by-step explanation:
