Question

你好！Please help me with this question. I will mark the correct answer brainlist, this is worth 20 points.

Answer 1

Answer:

See below

Step-by-step explanation:

1)

Once

$-3\sqrt{8} = -6\sqrt{2}$, it is an irrational number because $\sqrt{2}$ is irrational.

$2\sqrt{3}-\sqrt{27} = 2\sqrt{3}-3\sqrt{3}=-\sqrt{3}$, it is an irrational number because $\sqrt{3}$ is irrational

2) In order to compare those two fractions put them in the same denominator.

Once

$\dfrac{4}{13} = \dfrac{40}{130}$

$\dfrac{3}{10} = \dfrac{39}{130}$

So,

$\dfrac{39}{13} > \dfrac{40}{130}$

This is because, when two fractions have the same denominator, the larger number between them is the fraction with the lowest numerator.

Both are rational numbers because both denominator and numerator are integers.