Step-by-step explanation:
the speed of the first ship is 20 mph
and the second ship is 15 mph
Answer:
that was when I was in 1st grade. I was quite confused and didn't know what to do. We rehearsed first. I made a lot of mistakes but everything was fine until I got on stage. I think when I finished performing, it was my proudest time
Before the driver applies the brakes ( with the reaction time ):
d 1 = v0 · t = 20 m/s · 0.53 s = 10.6 m
After that:
v = v0 - a · t1
0 = 20 m/s - 7 · t1
7 · t1 = 20
t1 = 2.86 s
d 2 = v 0 · t1 - a · t1² / 2
d 2 = 20 m/s · 2.86 s - 7 m/s² · (2.86 s)²/2 = 57.2 m - 28.6 m = 28.6 m
d = d 1 + d 2 = 10.6 m + 28.6 m = 39.2 m
Answer: the stopping distance of a car is 39.2 m.
Answer:
D.x = 6; m∠XOY = 18°
Step-by-step explanation:
Supplementary angles add to 180 and complementary angles add to 90
∠WOZ + ∠WOX = 180
108 + ∠WOX = 180
∠WOX + ∠XOY = 90
∠WOX + 3x = 90
∠WOX = 90 -3x
Replace WOX in the first equation
108 + ∠WOX = 180
108 + 90 -3x = 180
Combine like terms
198 -3x = 180
Subtract 198 from each side
-3x = 180-198
-3x = -18
Divide by -3
-3x/-3 = -18/-3
x = 6
∠XOY = 3x = 3*6 = 18
Answer:
dude bace times hight 4×2×3
