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2 years ago

A line, y = mx + b, passes through the point (1, 6) and is parallel to

Mathematics

1 answer:

koban [17]2 years ago

8 0

Answer: b=6

Step-by-step explanation:

6 is in the y intercept place so it equals 6

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Which equation is equivalent to logx36=2

coldgirl [10]

Answer:

Which equation is equivalent to logx36=2

Exact Form:

x= $10\frac{1}{18}$

Decimal Form:

x=1.13646366

8 0

2 years ago

Out of 450 applicants for a job, 206 are male and 62 are male and have a graduate degree.

xxMikexx [17]

Answer:

0.3009 is the probability that the applicant has graduate degree given he is a male.

Step-by-step explanation:

We are given he following in the question:

M: Applicant is male.

G: Applicant have a graduate degree

Total number of applicants = 450

Number of male applicants = 206

$n(M) = 206$

Number of applicants that are male and have a graduate degree = 62

$n(M\cap G) = 62$

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

$P(M) = \dfrac{206}{450} = 0.4578$

$P(M\cap G) = \dfrac{n(M\cap G)}{n} = \dfrac{62}{450} = 0.1378$

We have to find the probability that the applicant has graduate degree given he is a male.

$P(G|M) = \dfrac{P(G\cap M)}{P(M)} = \dfrac{\frac{62}{450}}{\frac{206}{450}} = \dfrac{62}{206} = 0.3009$

Thus, 0.3009 is the probability that the applicant has graduate degree given he is a male.

5 0

2 years ago

A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro

pshichka [43]

Answer:

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed $\frac{dx}{dt}$ = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

$(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=(x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=rx$

$\frac{dh}{dt}=\frac{rx}{h}$

When automobile is 30 miles past the intersection,

For x = 30

$\frac{dh}{dt}=\frac{30r}{h}$

Since $h=\sqrt{d^{2}+(30)^{2}}$

Therefore,

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}$

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

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3 years ago

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Luba_88 [7]

Answer:

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