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3 years ago

SOMEONE PLZ HELP ME!!!!! Explain how you find a unit rate when given a rate.

Mathematics

1 answer:

vaieri [72.5K]3 years ago

3 0

Answer:

when giving a rate you need to get a unit rate which is a fraction with a 1 on top then you would divide by the same number as the number if you have 6/6 then divide by 6

Step-by-step explanation:

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I kinda got confused on this one <br> 25z - 8z + (-3z)

otez555 [7]

Answer:

The answer is 14z

Step-by-step explanation:

25z - 8z + (-3z)

-8z + (-3z) is the same thing as -8z - 3z, which equals -11z,

25z - 11z = 14z

7 0

3 years ago

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Write a polynomial function of least degree with integral coefficients that has the

frutty [35]

A polynomial function of least degree with integral coefficients that has the

given zeros $f(x)=x^4+x^3+9x^2+9x$

Given

Given zeros are 3i, -1 and 0

complex zeros occurs in pairs. 3i is one of the zero

-3i is the other zero

So zeros are 3i, -3i, 0 and -1

Now we write the zeros in factor form

If 'a' is a zero then (x-a) is a factor

the factor form of given zeros

$\:\left(x-3i\right)\left(x-\left(-3i\right)\right)\left(x-0\right)\left(x-\left(-1\right)\right)\\\left(x-3i\right)\left(x+3i\right)\left(x-0\right)\left(x+1\right)$

Now we multiply it to get the polynomial

$x\left(x-3i\right)\left(x+3i\right)\left(x+1\right)\\x\left(x^2+9\right)\left(x+1\right)\\x\left(x^3+x^2+9x+9\right)\\x^4+x^3+9x^2+9x$

polynomial function of least degree with integral coefficients that has the

given zeros $f(x)=x^4+x^3+9x^2+9x$

Learn more : brainly.com/question/7619478

6 0

3 years ago

Need this answer for this

Alexandra [31]

Answer:

the point (0,6) is the point that is 1/6 of the way

5 0

2 years ago

Caleb gets newsletters by e-mail. He gets one for sports every 5 days, one for model railroads every 10 days, and one for music

valentina_108 [34]

He would have to wait 40 more days

5 0

3 years ago

What is the measure of ABC?

lesantik [10]

Answer:

Step-by-step explanation:

85 degrees. Step-by-step explanation: From the diagram, it is clearly visible that the angle ∠ABC is formed by intersections of two chords AE and CD of the circle.

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3 years ago

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