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valentina_108 [34]
3 years ago
6

What is an equation of the line that passes through the points (0, 3) and (5, -3)?

Mathematics
1 answer:
shepuryov [24]3 years ago
3 0

Answer <u>(assuming it can be in slope-intercept form)</u>:

y = -\frac{6}{5} x+3  

Step-by-step explanation:

1) First, use the slope formula m =\frac{y_2-y_1}{x_2-x_1} to find the slope of the line. Substitute the x and y values of the given points into the formula and solve:

m =\frac{(-3)-(3)}{(5)-(0)} \\m = \frac{-3-3}{5-0}\\m = \frac{-6}{5}

So, the slope is -\frac{6}{5}.  

2) Now, use the slope-intercept formula y = mx + b to write the equation of the line in slope-intercept form. All you need to do is substitute real values for the m and b in the formula.

Since m represents the slope, substitute -\frac{6}{5} for it. Since b represents the y-intercept, substitute 3 for it. (Remember, the y-intercept is the point at which the line hits the y-axis. All points on the y-axis have an x-value of 0. Notice how the given point (0,3) has an x-value, too, so it must be the line's y-intercept.) This gives the following equation and answer:

y = -\frac{6}{5} x+3

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