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3 years ago

What is an equation of the line that passes through the points (0, 3) and (5, -3)?

Mathematics

1 answer:

shepuryov [24]3 years ago

3 0

Answer <u>(assuming it can be in slope-intercept form)</u>:

$y = -\frac{6}{5} x+3$

Step-by-step explanation:

1) First, use the slope formula $m =\frac{y_2-y_1}{x_2-x_1}$ to find the slope of the line. Substitute the x and y values of the given points into the formula and solve:

$m =\frac{(-3)-(3)}{(5)-(0)} \\m = \frac{-3-3}{5-0}\\m = \frac{-6}{5}$

So, the slope is $-\frac{6}{5}$ .

2) Now, use the slope-intercept formula $y = mx + b$ to write the equation of the line in slope-intercept form. All you need to do is substitute real values for the $m$ and $b$ in the formula.

Since $m$ represents the slope, substitute $-\frac{6}{5}$ for it. Since $b$ represents the y-intercept, substitute 3 for it. (Remember, the y-intercept is the point at which the line hits the y-axis. All points on the y-axis have an x-value of 0. Notice how the given point (0,3) has an x-value, too, so it must be the line's y-intercept.) This gives the following equation and answer:

$y = -\frac{6}{5} x+3$

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Half Angle Formula

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Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

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1 year ago

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kodGreya [7K]

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Step-by-step explanation:

Given that the perimeter of the triangle = 63 cm

And the length of one side = 21 cm

and one of the medians is perpendicular to one of its angle bisectors

Since triangle has 3 sides,

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Therefore each side length = 21 cm

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Answer:

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