What else would need to be congruent to show that ABC = PQR by sss

How do you solve this?

NNADVOKAT [17]

Answer:

C.)

Step-by-step explanation:

The graph is positive this time, so right away you can eliminate A and B.

If y=2x, the graph would be much steeper so the answer is C.) you can also check by graphing it in desmos.

4 0

2 years ago

Read 2 more answers

Given the sequence 8, 12, 16, 20, 24, what is the sum of the 31st and 19th terms?

erica [24]

Answer:

First term (a) =8

Common difference (d)= t2-t1

=12-8

=4

Now, sum of first 31th term (tn31) =n/2{2a+(n-1)d}

= 31/2{2×8+(31-1)4}

=31/2{16+(30×4)

=31/2(16+120)

=31/2×126

=31×63

Step-by-step explanation:

Similarly use 19 as (n) for the 19th term

7 0

2 years ago

O. Find the distance between P (10,-7) and Q (7,- 10). Leave your answer in radical<br> form.

mr Goodwill [35]

Answer:

$\sqrt{18}$ or $3\sqrt{2}$ units.

Step-by-step explanation:

To find the <em>distance between two points</em>, we can use the Distance Formula.

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

<u />

<u>Given:</u>

P (10, -7) ⇒ x₁ = 10, y₁ = -7

Q (7, -10) ⇒ x₂ = 7, y₂ = -10

Substitute the given values into the formula and simplify.

$\\\implies d=\sqrt{\bold{(7-10)}^2+\bold{(-10-(-7))}^2}\\\\\implies d=\sqrt{\bold{(-3)}^2+\bold{(-10+7)}^2}\\\\\implies d=\sqrt{9+\bold{(-3)}^2}\\\\\implies d=\sqrt{\bold{9+9}}\\\\\implies d=\sqrt{\bold{18}}\\\\\implies d=\sqrt{\bold{9}\times2}\\\\\implies d=3\sqrt{2}$