Answer:
<h2><u><em>
6. </em></u></h2><h2><u><em>
a. 11 and 2/3 yds. squared</em></u></h2><h2 /><h2><u><em>
b. Yes, the volume of the shed is 11 and 1/3 yards squared and what she's trying to put into it is only 10 yards squared, if put in properly, it will be able to fit.</em></u></h2><h2 /><h2><u><em>
7. 1,110 in. squared</em></u></h2>
Step-by-step explanation:
6.
a.
(10/3)*(14/9)*(9/4)
= 11 2/3
b.
Yes, because the volume of the shed is about 11.67 yards long, the 10 yards of wood will fit in the shed.
7.
For this one, we have to break it into two pieces.
(I made them into a small box and and big box)
The measurements of the small box are 7*5*6.
The measurements of the big box are 20*5*9.
Using this information, we can make the following equation and solve it quickly.
(7*5*6) + (20*5*9)
(210) + (900)
1,110
Thus, the volume of this box is 1,110 in. ^2
Answer:
x^2-3x-54
Step-by-step explanation:
(x+6)(x-9) Setup the roots
x^2-9x+6x-54 FOIL out the terms
x^2-3x-54 Add like terms together
Answer:
Step-by-step explanation:
-0.5(3x + 5) and -1.5x + 2.5
-0.5(3x + 5)...distribute the -0.5 thru the parenthesis
-1.5x - 2.5
no, these are not equivalent.... one is -1.5x + 2.5 and the other is -1.5x - 2.5....not the same
Answer:
0.6 miles per minute
Step-by-step explanation:
3/5 = 0.6/1 = 0.6
Answer:
d = 3.5t + 1
Step-by-step explanation:
The linear function would have to multiply the speed she runs at the track by the number of hours that she spent running. Then it should add this amount to the 1 mile that she walked to get to the track. If we use the variable d as the total distance that she ran and walked, and the variable t to represent time then we would create the following linear function/model.
d = 3.5t + 1
