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2 years ago

15

HELP FIND X AND Y PLS

1 answer:

S_A_V [24]2 years ago

6 0

Answer:

X=56 Y=56

Step-by-step explanation:

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LA plane is trying to travel 250 miles at a bearing of 20° E of S, however, it ends 230 miles away from the

Semmy [17]

Answer:

The wind pushed the plane $65.01$ miles in the direction of $45.56 ^{\circ}$ East of North with respect to the destination point.

Step-by-step explanation:

Let origin, O, br the starting point and point D be the destination at 250 miles at a bearing of 20° E of S, but due to wind let D' be the actual position of the plane at 230 miles away from the starting point in the direction of 35° E of South as shown in the figure.

So, we have |OD|=250 miles and |OD'|=230 miles.

Vector $\overrightarrow{DD'}$ is the displacement vector of the plane pushed by the wind.

From figure, the magnitude of the required displacement vector is

$|DD'|=\sqrt{|AB|^2+|PQ|^2}\;\cdots(i)$

and the direction is $\alpha$ east of north as shown in the figure,

$\tan \alpha=\frac{|PQ|}{|AB|}\;\cdots(ii)$

From the figure,

$|AB|=|OA-OB|$

$\Rightarrow |AB|=|OD\cos 20 ^{\circ}-OD'\cos 35 ^{\circ}|$

$\Rightarrow |AB|=|250\cos 20 ^{\circ}-230\cos 35 ^{\circ}|$

$\Rightarrow |AB|=45.52$ miles

Again, $|PQ|=|OP-OQ|$

$\Rightarrow |PQ|=|OD\sin 20 ^{\circ}-OD'\sin 35 ^{\circ}|$

$\Rightarrow |PQ|=|250\sin 20 ^{\circ}-230\sin 35 ^{\circ}|$

$\Rightarrow |PQ|=46.42$ miles

Now, from equations (i) and (ii), we have

$|DD'|=\sqrt{|45.52|^2+|46.42|^2}=65.01$ miles, and

$\tan \alpha=\frac{|46.42|}{|45.52|}$

$\alpha=\tan^{-1}\left(\frac{|46.42|}{|45.52|}\right)=45.56 ^{\circ}$

Hence, the wind pushed the plane $65.01$ miles in the direction of $45.56 ^{\circ}$ E astof North with respect to the destination point.

5 0

2 years ago

Please someone answer for this question

Maslowich

First one is 5/3
Second one is: 5
Third one is: 15

3 0

2 years ago

Read 2 more answers

Write a story to go with 3/4 times 1/2.

valina [46]

Answer:

2/3 = 0.666666667

<em><u>hopefully i helped :)</u></em>

<em><u></u></em>

8 0

2 years ago

Read 2 more answers

on a certain hot Summer's Day 613 people use the public swimming pool the daily prices are $1.75 for children $2.25 for adults t

Elodia [21]

389 children and 224 adults were at the pool that day.

Step-by-step explanation:

Cost of one child ticket = $1.75

Cost of one adult ticket = $2.25

Total people = 613

Total receipts worth = $1184.75

Let,

Number of children = x

Number of adults = y

According to given statement;

x+y=613 Eqn 1

1.75x+2.25y=1184.75 Eqn 2

Multiplying Eqn 1 by 1.75

$1.75(x+y=613)\\1.75x+1.75y=1072.75\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(1.75x+2.25y)-(1.75x+1.75y)=1184.75-1072.75\\1.75x+2.25y-1.75x-1.75y=112.00\\0.50y=112.00$

Dividing both sides by 0.50

$\frac{0.50y}{0.50}=\frac{112.00}{0.50}\\y=224$

Putting y=224 in Eqn 1

$x+224=613\\x=613-224\\x=389\\$

389 children and 224 adults were at the pool that day.

Keywords: linear equation, subtraction

Learn more about linear equations at:

#LearnwithBrainly

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3 years ago

lavan buys a house with a down payment of 12,000. The down payment is 10% of the price of the house house. How much will her mor

Tcecarenko [31]

Her mortgage will be 1,200.

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2 years ago