1.an = 3n - 1 2. an = 2(2n - 3) 3.an = 4^n 4.an = (2/3)^n 5. an = (-1)^n(n + 5) 6. an = (-1)^n + 1(n + 6) 7. an= n+3/2n-1 8. a1 = -5 and an = an-1 - 3 for n ≥ 2 9. a1 = -6 and an = -2an-1 for n ≥ 2 10.a1 = 4 and an = 3an-1 + 2 for n ≥ 2 11. Find a8 when a1...
The error is that 9 shouldnt be written as nine it should be written as 3x3 or 3^2. So the answer should be 2^3 x 3^2 because 9 can be divided into even more prime factors of 72.
