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3 years ago

Express 5% as a decimal

Mathematics

1 answer:

IRINA_888 [86]3 years ago

6 0

Answer:

.05

Step-by-step explanation:

you divide 5 by 100 which makes it .05

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What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (−2, 4)?

GrogVix [38]

First find the slope of the given line like this:
$5x + 2y = 12\\2y=-5x+12\\y=\frac{-5}{2}x+6$
If two lines are parallel, then they have the same slope, so the equation we are looking for is in the form:
$y=\frac{-5}{2}x+a$ and we have to find b using the given point like this:
Substitute x = -2 and y=4 in the above equation like this and solve for a:
$4=\frac{-5}{2}(-2)+a$
$4=5+a$
$a=4-5=-1$
The equation of the line is then the following:
$y=\frac{-5}{2}x-1.$

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Round 17 5/8 to the nearest whole number

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Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

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4 years ago