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3 years ago

help please name the meidem of triangle MNO please i really need help or explain how to figure it out

Mathematics

1 answer:

Dmitry [639]3 years ago

6 0

Answer:

If you find the middle of any side of a triangle, you have found its midpoint. From that midpoint, you can construct a line segment to the opposite interior angle. That constructed line from the midpoint of a side to the opposite interior angle is a median.

Step-by-step explanation:

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How many liters of water should be added to 18 liters of a 14% bleach solution so that the resulting solution contains only 10%

KiRa [710]

18 liters of 14% bleach contains 0.14×18 = 2.52 liters of bleach.

Adding $x$ liters of pure water to the solution increases the total volume to $18+x$ liters without changing the total amount of bleach.

To end up with a 10% bleach solution, we must add

$\dfrac{2.52}{18+x} = 0.10 \implies 2.52 = 1.8 + 0.10x \implies 0.10x = 0.72 \implies x=\boxed{7.2}$

liters of water.

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2 years ago

Solve.

uysha [10]

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divided by 7/8 divided by 7/8
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3 years ago

The solution for the following scenario: x > 25

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3 years ago

Which is the equation of a line with a slope of -1/3 and a yintercept at (0, 1)?

posledela

Y = mx + b

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1 = (-1/3)(0) + b
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4 years ago

Find the longer leg of the triangle.

Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

The length of the hypotenuse (the side opposite to the right angle) is given.
The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let $\text{Opposite}$ denotes the length of the side opposite to the $30^{\circ}$ acute angle, and $\text{Adjacent}$ be the length of the side next to this $30^{\circ}$ acute angle.

$\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}$ .

Similarly,

$\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}$ .

The longer leg in this case is the one adjacent to the $30^{\circ}$ acute angle. The answer will be $3$ .

There's a shortcut to the answer. Notice that $\sin{30^{\circ}} < \cos{30^{\circ}}$ . The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the $30^{\circ}$ angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship $\sin{\theta} < \cos{\theta}$ holds for all acute angles? (That is, $0^{\circ} < \theta$ ?) It turns out that:

$\sin{\theta} < \cos{\theta}$ if $0^{\circ} < \theta$ ;
$\sin{\theta} > \cos{\theta}$ if $45^{\circ} < \theta$ ;
$\sin{\theta} = \cos{\theta}$ if $\theta = 45^{\circ}$ .

4 0

3 years ago

Read 2 more answers