For part A, The answer is that the car gets better gas mileage. We can see it from the graph that the number of gallons used is on the X axis, and the distance traveled using those number of gallons is on the Y axis. The easiest way to compare would be to look at the 1 gallon of gas. You can see that you can travel 25 miles on 1 gallon of gas. The truck on the other hand will get you 18 miles per gallon. Imagine putting 1 in for X, the Y value would be 18 if you did this. The graph just shows us a visual way of saying the same thing. To determine how much farther the car with a girl on 8 gallons of gas, you would just multiply 8 by 25 for the number of miles traveled by the car. You would multiply 8 by 18 to find the number of miles traveled for the truck. The answers are 200 miles for the car and 144 miles for the truck. 200-144=56 miles farther for the car.

6 0

3 years ago

Mia jogs 3 kilometers in 20 minutes. There are about 0.6 miles in a kilometer. What is Mia’s approximate speed in miles per minu

scoundrel [369]

Speed is the ditance traveled by a certain object given a certain time span. To solve this problem we need to divide the distance by the time given. Before that, the problem asked us to get the speed in terms of miles per minute and we are given a distance of 3 kilometer. We have to convert this to miles. 3km(0.6miles/km) = 1.8 miles. The speed is then 1.8/20 = 0.09mi/min.

3 0

3 years ago

Liam and Harper are racing on a track. Liam runs 4 miles per hour and gets a 0.25 mile head start. Harper runs 0.5 miles per hou

Scilla [17]

Answer:

30 minutes = 0.5 hour

Step-by-step explanation:

0.5 miles faster than Liam:

4x + 0.25 = 4.5x

0.25 = 4.5x - 4x

0.25 = 0.5x

x = 0.25 / 0.5

x = 0.5 hours

x = 30 minutes

4 0

3 years ago

Billy is monitoring the exponential decay of a radioactive compound. He has a sample of the compound in a test tube in his lab.

Over [174]

Solution:

Formula for radioactive Decay is given by

$R_{0}= R(1-\frac{S}{100})^t$

$R_{0}$ = Initial Population

R = Remaining population after time in hours

Rate of Decay = S % per hour

Initial Population = 72 grams

Final population = 15 grams

Rate of Decay = 35 % per hour

Substituting the values to get value of t in hours

$72=15(1-\frac{35}{100})^t\\\\ 4.8= (0.65)^t\\\\ t= -3.64$ →→1 St expression

But taking positive value of t , that is after 3.64 hours the sample of 72 grams decays to 15 grams at the rate of 35 % per hour.

Now , it is also given that, Once the sample reaches a mass of 15 grams, Billy will continually add more of the compound to keep the sample size at a minimum of 15 grams.

Substituting these in Decay Formula

Final Sample = 15 gm

Starting Sample = 15 +k, where k is amount of sample added each time to keep the final sample to 15 grams.

Time is over 3.64 hours i.e new time = 3.64 + t

Rate will remain same i.e 35 % per hour.

$15=(15+k)(1-\frac{35}{100})^{3.64+t}$ →→→ Final expression (Second) , that is inequalities can be used to determine the possible mass of the radioactive sample over time.

5 0

3 years ago

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