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3 years ago

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Erica uses 9 gallons of gas to drive 198 miles. How many miles can he drive using 1 gallon of gas?

1 answer:

lara31 [8.8K]3 years ago

3 0

Answer:

198 / 9 = 22

Step-by-step explanation:

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lesya [120]

What is the question?

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3 years ago

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Can 1 be expressed as a fraction

elixir [45]

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2 years ago

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The line $y = 3$ intersects the graph of $y = 4x^2 + x - 1$ at the points $A$ and $B$. The distance between $A$ and $B$ can be w

raketka [301]

Answer:

61

Step-by-step explanation:

Let's find the points $A$ and $B$ .

We know that the $y$ -coordinates of both are $3$ .

So let's first solve:

$3=4x^2+x-1$

Subtract 3 on both sides:

$0=4x^2+x-1-3$

Simplify:

$0=4x^2+x-4$

I'm going to use the quadratic formula, $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , to solve.

We must first compare to the quadratic equation, $ax^2+bx+c=0$ .

$a=4$

$b=1$

$c=-4$

$\frac{-1 \pm \sqrt{1^2-4(4)(-4)}}{2(4)}$

$\frac{-1 \pm \sqrt{1+64}}{8}$

$\frac{-1 \pm \sqrt{65}}{8}$

Since the distance between the points $A$ and $B$ is horizontal. We know this because they share the same $y-coordinate$ .This means we just need to find the positive difference between the $x$ -values we found for the points of $A$ and $B$ .

So that is, the distance between $A$ and $B$ is:

$\frac{-1+\sqrt{65}}{8}-\frac{-1-\sqrt{65}}{8}$

$\frac{-1+\sqrt{65}+1+\sqrt{65}}{8}$

$\frac{2\sqrt{65}}{8}$

$\frac{\sqrt{65}}{4}$

If we compare this to $\frac{\sqrt{m}}{n}$ , we should see that:

$m=65 \text{ and } n=4$ .

So $m-n=65-4=61$ .

5 0

3 years ago

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which of the following best describes 4^2/3? a. sq root of 16, b. cube root of 4, c. sq root of four, d. cube root of 16

son4ous [18]

Answer: D) cube root of 16

================================================

Explanation:

The rule we use is

$x^{m/n} = \sqrt[n]{x^m}$

In this case, x = 4, m = 2 and n = 3.

So,

$x^{m/n} = \sqrt[n]{x^m}\\\\\\4^{2/3} = \sqrt[3]{4^2}\\\\\\4^{2/3} = \sqrt[3]{16}\\\\\\$

Showing that the original expression turns into the cube root of 16.

4 0

3 years ago

Thirty-three college freshmen were randomly selected for an on-campus survey at their university. The participants' mean GPA was

Ivan

Answer: $\pm0.1706$

Step-by-step explanation:

Given : Sample size : n= 33

Critical value for significance level of $\alpha:0.05$ : $z_{\alpha/2}= 1.96$

Sample mean : $\overline{x}=2.5$

Standard deviation : $\sigma= 0.5$

We assume that this is a normal distribution.

Margin of error : $E=\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

i.e. $E=\pm (1.96)\dfrac{0.5}{\sqrt{33}}=\pm0.170596102837\approx\pm0.1706$

Hence, the margin of error is $\pm0.1706$

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3 years ago