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Ratling [72]
3 years ago
6

Solve this system using the linear combination method. Show your work and explain each step. 2x + y = 8 x − y = 4

Mathematics
1 answer:
Furkat [3]3 years ago
3 0

Answer:

Step-by-step explanation:

Subtract 2x

from both sides of the equation.

y=8−2x

x−y=2

Replace all occurrences of y

in x−y=2 with 8−2x

.

y=8−2x

x−(8−2x)=2

Simplify the left side.

Tap for more steps...

y=8−2x

3x−8=2

Solve for x

in the second equation.

Tap for more steps...

y=8−2x

x=103

Replace all occurrences of x

in y=8−2x with 103

.

y=8−2(103)

x=103

Simplify 8−2(103)

.

Tap for more steps...

y=43

x=103

The solution to the system of equations can be represented as a point.

(103,43)

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2m divided by 3/9; m = 3/2
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Answer:

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Step-by-step explanation:

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Then you would want to solve. So, you would need to divide 2 by 1/3 which would give you 9.

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3 years ago
What is the slope of the line through (2,-2)(2,−2)left parenthesis, 2, comma, minus, 2, right parenthesis and (9,3)(9,3)left par
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F
Svet_ta [14]

Answer:

A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36

Step-by-step explanation:

The equations are:

y = x^{2} + 2x + 3

y = 2x + 12

The two graphs intersect when:

x^{2} + 2x + 3 = 2x + 12

x^{2} = 0

x_{1}  = 3\\x_{2}  = -3

To find the area under the curve for the first equation:

A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx

To find the area under the curve for the second equation:

A_{2} = \int\limits^3__-3}{2x + 12} \, dx

To find the total area:

A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx

Simplifying the equation:

A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).  

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3 years ago
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