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3 years ago

Solve this system using the linear combination method. Show your work and explain each step. 2x + y = 8 x − y = 4

Mathematics

1 answer:

Furkat [3]3 years ago

3 0

Answer:

Step-by-step explanation:

Subtract 2x

from both sides of the equation.

y=8−2x

x−y=2

Replace all occurrences of y

in x−y=2 with 8−2x

y=8−2x

x−(8−2x)=2

Simplify the left side.

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y=8−2x

3x−8=2

Solve for x

in the second equation.

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y=8−2x

x=103

Replace all occurrences of x

in y=8−2x with 103

y=8−2(103)

x=103

Simplify 8−2(103)

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y=43

x=103

The solution to the system of equations can be represented as a point.

(103,43)

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Answer:

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3 years ago

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3 years ago

Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F

Svet_ta [14]

Answer:

$A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36$

Step-by-step explanation:

The equations are:

$y = x^{2} + 2x + 3$

$y = 2x + 12$

The two graphs intersect when:

$x^{2} + 2x + 3 = 2x + 12$

$x^{2} = 0$

$x_{1} = 3\\x_{2} = -3$

To find the area under the curve for the first equation:

$A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

To find the area under the curve for the second equation:

$A_{2} = \int\limits^3__-3}{2x + 12} \, dx$

To find the total area:

$A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

Simplifying the equation:

$A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx$

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).

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